Mass of potassium nitrate is needed to generate 215.0 L of gas, composed of 111.0 L of N₂ and 104.0 L of O₂ at 0.920 atm and 291 K, using these two reactions is 1186.75 g.
The reactions are :
2KNO₃ ---> 2KNO₂ + O₂
4KNO₂ ----> 2K₂O + 3O₂ + 2N₂
Therefore,
4KNO₃ ----> 2K₂O + 5O₂ + 2N₂
using the formula:
PV = nRT
moles of N₂ = PV / RT
P = 0.920 atm
T =291 K
R = 0.082 Latm/mol/k
moles of N₂ = 4.279 mol
moles of O₂ = (0.92 × 104) / 0.082 × 291
= 4.00 mol
from the equation .
moles of potassium nitrate to produce nitrogen = 2 × 4.279
= 8.55 mol
moles of nitrate tp produce oxygen = (4 / 5) × 4
= 3.2 mol
total moles of nitrate = 8.55 mol + 3.2 mol
= 11.75 mol
mass of potassium nitrate = number of moles × molar mass
= 11.75 × 101
= 1186.75 g
Thus, Mass of potassium nitrate is needed to generate 215.0 L of gas, composed of 111.0 L of N₂ and 104.0 L of O₂ at 0.920 atm and 291 K, using these two reactions is 1186.75 g.
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