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forsale [732]
3 years ago
8

Which is a word phrase for the variable expression? 3(n – 1) A. three times the quotient of a number n and 1 B. three more than

the difference of a number n and 1 C. one less than the product 3 and a number n D. three times the difference of a number n and 1
Mathematics
1 answer:
sergey [27]3 years ago
8 0
D. three times the difference of a number n and 1
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Well Area is multiplying all the angles so just multiply the angles and your good hope this helps
7 0
2 years ago
Read 2 more answers
Find the value of x. Round the length to nearest tenth.
Lady_Fox [76]

From the law of sines, we have

l = h\sin(\theta) = h\cos(\alpha)

where l is the leg we're interested in, h is the hypothenuse, \theta is the angle opposite to l, and \alpha is the angle between l and h.

So, in the first case, we can use

x = 15\sin(35) \approx 8.6

And in the second excercise, we use

x = 11\cos(44) \approx 7.6

5 0
3 years ago
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Marion bought 14 packages of plastic frog and lizard fishing lures. She bought frog lures in packages of 4 and lizard lures in p
tatuchka [14]

Answer:

Marion bought 6  frog lures and 8 lizard fishing lures.

Step-by-step explanation:

Let f represent frog lures and l represent lizard lures.


The total packages Marion bought is

f+l=14...eqn1


If she bought frog lures in packages of 4 and lizard lures in packages of 6 for a total of 72 lures, then

4f+6l=72...eqn2


We make f the subject in equation 1 and put it into equation 2 to get;

f=14-l...eqn3


We put equation 3 into equation 2 to get;

4(14-l)+6l=72


\Righttarrow 2(14-l)+3l=36


We expand the bracket to get;

28-2l+3l=36


-2l+3l=36-28


l=8


We put l=8 into equation 3 to get;

f=14-8


f=6

Therefore Marion bought 6  frog lures and 8 lizard fishing lures.


6 0
3 years ago
Who replaced circles with ellipses in a heliocentric model of the universe
Setler79 [48]
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7 0
3 years ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
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