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ra1l [238]
3 years ago
8

If the average mass of a peacock is 4.95 kilograms, what is the average mass of a peacock In grams?

Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

4950g

Step-by-step explanation:

firstly remember the formula for converting from kg to g

Kilograms ( kg) to grams(g)

1 kg = 1000g

therefore to convert 4.95 kg to g

is 4.95 * 1000

=<u> 4950g</u>

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This is the answer to the question.
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Graph a right triangle with the two points 4,5 and -4,8​
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Please write points using parentheses:  (4, 5) and (-4, 8}.

​

(4, 5) is in the 1st quadrant and (-4, 8} is in the 2nd. Reversing the order of these two points yields (-4, 8) and (4, 5).  From this we can see that while moving from (-4, 8) to (4, 5) involves following a line with negative slope (because the y-coordinate decreases from 8 to 5 as the x-coordinate increases from -4 to +4).  This sloping line is the hypotenuse of a right triangle.  Draw a vertical line segment through (-4, 8) and a horizontal line segment through (4, 5).  This hypotenuse, the vertical line segment and the horizontal line segment are the boundaries of the desired right triangle.  

6 0
3 years ago
Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft. what will be
ira [324]

The length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.

<h3>What is the Pythagoras theorem?</h3>

The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

We have:

Frankie wants to build a path from one corner of his yard to the opposite corner. his yard measures 20 ft. x 32 ft.

From the Pythagoras theorem:

Perpendicular(P) = 32 ft

Base(B) = 20 ft

H = √(32²+20²)

H = √1424

H = 37.7 ft

Thus, the length of his path to the nearest tenth of a foot is 37.7 ft option fourth is correct.

Learn more about Pythagoras' theorem here:

brainly.com/question/21511305

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5 0
1 year ago
38 ×29 use rounding to estimate each product
nydimaria [60]
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8 0
3 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

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The value of h(2x+1).

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Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

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3 0
3 years ago
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