C=2pir
c=25.12
25.12=2pir
divide both sides by 2
12.56=pir
divide both sides by 3.14 since we will use pi=3.14
4=r
radius is 4cm
First we take the number as it is. Second, we look at the last number. 6 is rounds up to ten which rounds the 3 up to a 4. So now we come up with 8.4, but that isn't a whole number. We can then round 4 to 0 because it's closer to 0 on a number line. Now, our answer is 8.0, but, in order to have a whole number, we can't have any decimals. we can, then, take away the 0 and the decimal, which leaves us 8, and 8 is a whole number; we can now say the answer is 8. :)
Yes This Is Possible. This Would Happen If The Lines Never Intersected With Each Other. If This Was The Case, There Would Be No Point That Lies On Both Lines. Have A Great Day!
Answer:
12
Step-by-step explanation:
x^2 - a
If a is a perfect square we could factor
x^2 - b^2 = (x-b)(x+b)
So a cannot be 36,49,81 since they are perfect squares
a must be 12
