Which dinosaur had teeth that measured six inches

seraphim [82]

They all have segmented limbs, a hard exoskeleton, a pair of antennae and a segmented body.

4 0

2 years ago

A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the

Anni [7]

Answer:

$I=38.181\ A$ is the current through the body of the man.

$E=34.5\ J$ energy dissipated.

Explanation:

Given:

time for which the current lasted, $t=43\times 10^{-6}\ s$

potential difference between the feet, $V=21000\ V$

resistance between the feet, $R=550\ \Omega$

Now, from the Ohm's law we have:

$I=\frac{V}{R}$

$I=\frac{21000}{550}$

$I=38.181\ A$ is the current through the body of the man.

Energy dissipated in the body:

$E=I^2.R.t$

$E=38.181^2\times 550\times 43\times 10^{-6}$

$E=34.5\ J$

5 0

2 years ago

7. Which quantity is the transfer of energy? force motion work

Arisa [49]

In this exercise we have to know the definition of energy to understand what is transferred to a body, like this:

Work

<h2>What is energy?</h2>

Despite being used in many different contexts, the scientific use of the word energy has a well-defined and precise meaning: Innate potential to perform work or perform an action. Anything that is working, moving another object, or heating it up, for example, is expending (transferring) energy.

With this definition we can say that the only alternative that responds to this is work.

See more about energy at brainly.com/question/1932868

6 0

1 year ago

Read 2 more answers

A 50.0 kg object is moving at 18.2 m/s when a 200 N force

gayaneshka [121]

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a = force ÷ mass

a = $\frac{-200}{50}$ = -4 m/s²

we get here now required time that is

required time = $\frac{V_{(final)} - V_{(initial)}}{a}$ ...............1

put here value

required time = $\frac{12.6-18.2}{-4}$

so distance will be

distance = $\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}$ ........2

distance = $\frac{12.6}^2 -{18.2}^2}{2\times (-4)}$

distance = 21.56 m

7 0

2 years ago

How much force is needed to lift a 25-kg mass at a constant verlocity?

Troyanec [42]

-- In order to achieve constant verlocity, the net force on the mass must be zero. So if there ARE any forces acting on it, they must be balanced.

-- There is already a force on the mass that can't be eliminated . . . the force of gravity.

-- That force due to gravity is (mass x gravity) = (25 kg)(9.8 m/s²) = 245N in the downward direction.

-- In order to 'balance' the forces and make them add up to zero, we have to provide another force of 245N, all in the upward direction.

-- Then the forces on the object will be balanced, the NET force on it will be zero, and whichever way you start it moving, it will continue to move at a cornstant verlocity.

5 0

2 years ago

Read 2 more answers