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DerKrebs [107]
3 years ago
14

Which dinosaur had teeth that measured six inches

Physics
1 answer:
Rudik [331]3 years ago
7 0

Answer:

Tyrannosaurus rex

You might be interested in
Help please*_*
DochEvi [55]

Answer:

3.83×10⁻¹⁹ J

Explanation:

The energy of a photon can be found using the formula: E=hc/λ

  • h is Planck's Constant which is approximately 6.63×10⁻³⁴
  • c is the speed of light which we'll round to 3.00×10⁸
  • λ is the wavelength of the photon. You typed 5200 but that's not even within the visible light spectrum's wavelength range, so I'm going to assume you meant 520 nm; or 5.20×10⁻⁷ m.

Plugging all that info in should give approximately 3.83×10⁻¹⁹ Joules of energy.

(You could get slight variations depending on what you chose to round up or down or not at all.)

5 0
3 years ago
If you wanted to get yellow light , what part of the of the spectrum would the color filter have to absorb ?
densk [106]
The filter would need to absorb every color EXCEPT yellow. It would have to absorb red orange green blue and violet.
4 0
3 years ago
factors that affect health, including genetic, lifestyle, socioeconomic, and physical environmental factors.​
scZoUnD [109]
Yes? I think a tutor would help with this!!!!
5 0
3 years ago
Air, considered an ideal gas, is contained in an insulated piston-cylinder assembly outfitted with a paddle wheel. It is initial
Maru [420]

Our data are,

State 1:

P_1= 10psi=68.95kPa\\V_1 = 1ft^3=0.02831m^3\\T_1 = 100\°F = 310.93K

State 2:

P_2 =5psi=34.474kPa\\V_2 = 3ft^3=0.0899m^3

We know as well that 3BTU=3.16kJ/K

To find the mass we apply the ideal gas formula, which is given by

P_1V_1=mRT_1

Re-arrange for m,

m= \frac{P_1V_1}{RT_1}\\m= \frac{68.95*0.02831}{(0.287)310.9}\\m=0.021893kg=0.04806lbm\\

Because of the pressure, temperature and volume ratio of state 1 and 2, we have to

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Replacing,

T_2 = \frac{P_2V_2}{P_1V_1}T_1\\T_2 =\frac{34.474*0.0844}{68.95*0.02831}*310.93\\T_2 = 464.217K=375.5\°F

For conservative energy we have, (Cv = 0.718)

W = m C_v = 0.718  \Delta T +dw\\dw = W - mv\Delta T\\dw = 3.16-(0.0218*0.718)(454.127-310.93)\\dw = 0.765kJ=0.72BTU

3 0
3 years ago
How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius
mixas84 [53]

The magnitude of static friction is

<em>f</em> = <em>mv</em> ²/<em>r</em>

(i.e. the net force acting on the car parallel to the road points toward the center of the curve)

while the net vertical force must be

∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0

because the car is otherwise in equilibrium. Then

==>   <em>n</em> = <em>mg</em>

==>   <em>f</em> = <em>µn</em> = <em>µmg</em> = <em>mv</em> ²/<em>r</em>

==>   <em>µ</em> = <em>v</em> ²/(<em>rg</em>)

We have

<em>v</em> = 101 km/h ≈ 28.1 m/s

<em>r</em> = 110 m

<em>g</em> = 9.80 m/s²

so that

<em>µ</em> = (28.1 m/s)² / ((110 m) <em>g</em>) ≈ 0.730

6 0
3 years ago
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