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iogann1982 [59]

3 years ago

8

A farmer wants to grow a crop of tomatoes that is resistant to disease and drought while producing larger fruit with a bright co

lor. Which plant should the farmer select to cross to get the desired combination of traits? A. 1 and 2 B. 2 and 3 C. 1 and 4 D.3 and 4

1 answer:

lilavasa [31]3 years ago

5 0

Answer:

Ez that's B I did that question before.

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Which of the following are true for acceleration?

Fittoniya [83]

The SI unit for acceleration is m/s2 ( D)

6 0

3 years ago

Earlier we discussed the concept of isostasy, where lower density rocks rise higher than higher density rocks. How is the variat

Elena L [17]

The variation of water depth at spreading centers (ridges) controlled by isostasy as convective cooling cools the rocks much more effectively the than heat conduction.

<h3>What is convective heat transfer?</h3>

When heat transfer takes place between the two fluids in direct or indirect contact.

The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.

Thus, the convective cooling cools the rocks much more effectively the than heat conduction.

Learn more about convective heat transfer

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4 0

2 years ago

11)A 1100 kg car travels on a straight highway with a speed of 30 m/s. The driver sees a red light ahead and applies her

cestrela7 [59]

Answer:

Time taken = 8.25 second

Explanation:

Given:

Force = 4000 N

Force = ma

4,000 = (1100)(a)

Acceleration = 3.6363 m/s²

v = u + at

0 = 30 + (3.6363)t

Time taken = 8.25 second

3 0

3 years ago

A sound wave is an example of an electromagnetic wave in nature. true or false?

Natasha2012 [34]

False. A sound wave is an example of a mechanical wave, not an EM wave.

Hope this helps! :)

5 0

4 years ago

Read 2 more answers

Three children are riding on the edge of a merry-go-round that is 182 kg, has a 1.60 m radius, and is spinning at 15.3 rpm. The

Korolek [52]

Answer:

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

Explanation:

The merry-go-round can be represented by a solid disk, whereas the three children can be considered as particles. Since there is no external force acting on the system, we can apply the principle of angular momentum conservation:

$\left(\frac{1}{2}\cdot M + m_{1}+m_{2} + m_{3} \right)\cdot R^{2}\cdot \dot n_{o} = \left(\frac{1}{2}\cdot M + m_{1} + m_{3})\cdot R^{2}\cdot \dot n_{f}$ (1)

Where:

$M$ - Mass of the merry-go-round, in kilograms.

$m_{1}$ , $m_{2}$ , $m_{3}$ - Masses of the three children, in kilograms.

$R$ - Radius of the merry-go-round/Distance of the children with respect to the center of the merry-go-round, in meters.

$\dot n_{o}$ , $\dot n_{f}$ - Initial and final angular speed, in revolutions per minute.

If we know that $M = 182\,kg$ , $m_{1} = 17.4\,kg$ , $m_{2} = 28.5\,kg$ , $m_{3} = 32.8\,kg$ , $R = 1.60\,m$ and $\dot n_{o} = 15.3\,\frac{rev}{min}$ , then the final angular speed of the system is:

$\dot n_{f} = \dot n_{o}\cdot \left(\frac{\frac{1}{2}\cdot M + m_{1} + m_{2} + m_{3} }{\frac{1}{2}\cdot M + m_{1} + m_{3} } \right)$

$\dot n_{f} = \left(15.3\,\frac{rev}{min} \right)\cdot \left[\frac{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg +28.5\,kg + 32.8\,kg }{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg + 32.8\,kg } \right]$

$\dot n_{f} = 18.388\,\frac{rev}{min}$

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

7 0

3 years ago