What is clean Cole technology
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Complete Question
A thin film in air is made by putting a thin layer of acetone (n = 1.25) on a layer of water
(n = 1.33). When visible light (400 nm – 700 nm) shines normally on the film an observed from above, the bright reflected light looks kind of “purplish” with red light of wavelength 650 nm mixed some blue giving it that appearance and “greenish” light of wavelength 520 nm is completely destroyed. Determine the thickness of the acetone film. (you only need to worry about the red and green wavelengths, not the blue)
Answer:
The thickness of acetone is
Explanation:
A diagram showing this process is shown on the first uploaded image
From the question we are told that
The refractive index of acetone is
The refractive index of water is
The wavelength of the reflected light is
The wavelength of the destroyed light is
Looking at the given data we can see that the
This means that the light which the acetone-water layer would reflect will have a phase shift of
Again this make us to understand that the light reflected at the acetone layer will also have a phase shift of
Since they would be having the same phase shift the two light would interfere
For interference the condition for minima is mathematically represented as
Where d is the thickness of acetone
Substituting values
Answer:
M = 5.882 10²³ kg
Explanation:
Let's use Newton's second law to analyze the satellite orbit around Mars.
F = m a
force is universal attraction and acceleration is centripetal
a = v²/ R
the modulus of velocity in a circular orbit is constant
v= d/T
the distance of the cicule is
d =2pi R
a = 2pi R/T
we substitute
- G m M / R² = m ( )
G M =
M =
the distance R is the distance from the center of the planet Mars to the center of the satellite Deimos
R = 23460 km = 2.3460 10⁷ m
the period of the orbit is
T = 1,263 days = 1,263 day (24 h / 1 day) (3600s / h)
T = 1.0912 10⁵ s
let's calculate
M =
M = 509.73418 10²¹ /8.66640 10⁻¹
M = 58.817 10²² kg
M = 5.882 10²³ kg