Container A and container B have leaks. Container A has 800 milaliters of water and is leaking 6 milaliters per minute. Containe
r B has 1000 milaliters and is leaking 10 milaliters per minute. How many minutes will it take for the two containers to have the same amount of water
1 answer:
Answer:
50 minutes
(1000-50 (10))=(800-50 (6))
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