Question

Container A and container B have leaks. Container A has 800 milaliters of water and is leaking 6 milaliters per minute. Container B has 1000 milaliters and is leaking 10 milaliters per minute. How many minutes will it take for the two containers to have the same amount of water

Answer 1

Answer:

50 minutes

(1000-50 (10))=(800-50 (6))