Answer:
<em>Heat</em> is the total energy of molecules moving around. <em>Temprature</em> is a measure of the average energy of molecules motion.
Answer : The molar heat of solution of KBr is 19.9 kJ/mol
Explanation :
Mass of KBr = 7.00 g
Molar mass of KBr = 119 g/mole
Heat capacity = 2.72 kJ/K
Change in temperature = 0.430 K
First we have to calculate the moles of KBr.
![\text{ Moles of }KBr=\frac{\text{ Mass of }KBr}{\text{ Molar mass of }KBr}=\frac{7.00g}{119g/mole}=0.0588moles](https://tex.z-dn.net/?f=%5Ctext%7B%20Moles%20of%20%7DKBr%3D%5Cfrac%7B%5Ctext%7B%20Mass%20of%20%7DKBr%7D%7B%5Ctext%7B%20Molar%20mass%20of%20%7DKBr%7D%3D%5Cfrac%7B7.00g%7D%7B119g%2Fmole%7D%3D0.0588moles)
Now we have to calculate the heat of the reaction.
![q=c\times \Delta T](https://tex.z-dn.net/?f=q%3Dc%5Ctimes%20%5CDelta%20T)
where,
q = amount of heat = ?
= heat capacity = ![2.72kJ/K](https://tex.z-dn.net/?f=2.72kJ%2FK)
= change in temperature = 0.430 K
Now put all the given values in the above formula, we get:
![q=2.72kJ/K\times 0.430K](https://tex.z-dn.net/?f=q%3D2.72kJ%2FK%5Ctimes%200.430K)
![q=1.17kJ](https://tex.z-dn.net/?f=q%3D1.17kJ)
Now we have to calculate the molar heat of solution of KBr.
![\text{Molar heat of solution of }KBr=\frac{q}{n}](https://tex.z-dn.net/?f=%5Ctext%7BMolar%20heat%20of%20solution%20of%20%7DKBr%3D%5Cfrac%7Bq%7D%7Bn%7D)
where,
n = number of moles of KBr
![\text{Molar heat of solution of }KBr=\frac{1.17kJ}{0.0588moles}=19.9kJ/mol](https://tex.z-dn.net/?f=%5Ctext%7BMolar%20heat%20of%20solution%20of%20%7DKBr%3D%5Cfrac%7B1.17kJ%7D%7B0.0588moles%7D%3D19.9kJ%2Fmol)
Therefore, the molar heat of solution of KBr is 19.9 kJ/mol
Aye daddy
Lucky thing i just came back xD
Its 78.66 to the nearest sig fig
U can google it 2
Since it takes 4ever to type it out i wrote it intead srry if its messy lol
Answer:
31.58 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) of gas = 1.90 moles
Initial volume (V₁) = 40 L
Final mole (n₂) = 1.90 – 0.40 = 1.5 moles
Final volume (V₂) =.?
The final volume of the gas can be obtained as follow;
V₁ / n₁ = V₂ / n₂
40 / 1.9 = V₂ / 1.5
Cross multiply
1.9 × V₂ = 40 × 1.5
1.9 × V₂ = 60
Divide both side by 1.9
V₂ = 60 / 1.9
V₂ = 31.58 L
Thus, the final volume of the gas is 31.58 L
1) (C2H5)2CBrCH2CH3 is the answer
explaiation:-
so when HBr is added to an alkene , according to the Markonicoff's rule ...H atoms are bonded to the C containing the most amount of H and Br is added to the other C.
2) Just add alkoholic KOH∆