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3 years ago

For the balanced chemical reaction

Chemistry

1 answer:

musickatia [10]3 years ago

5 0

Answer:

150

Explanation:

C₄H₂OH + 6O2 → 4CO2 + 5H₂O

We can <u>find the equivalent number of O₂ molecules for 100 molecules of CO₂</u> using a <em>conversion factor containing the stoichiometric coefficients of the balanced reaction</em>, as follows:

100 molecules CO₂ * $\frac{6moleculesO_2}{4moleculesCO_2}$ = 150 molecules O₂

150 molecules of O₂ would produce 100 molecules of CO₂.

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At the half equivalence point [HA] = [A-] and pH = pKa

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3 years ago

How many grams of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel?

Nimfa-mama [501]

Answer: 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

Explanation:

According to the dilution law,

$C_1w_1+C_2w_2=C_3w_3$

where,

$C_1$ = concentration of ist progesterone gel = 8%w/w

$w_1$ = weight of ist progesterone gel = x g

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$w_2$ = weight of another progesterone gel = 1.45 g

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$w_3$ = weight of resulting progesterone gel = (x+1.45) g

$8\times x+4\times 1.45=5.5\times (x+1.45)$

$x=0.87$

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4 years ago

Resource depletion, pollution, and habitat lose are all environmental problems cause by what factor

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All problems are caused by a factor in which human beings play an important role in its cause.

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3 years ago

Identify what kind of ligand (weak or strong), what kind of wavelength (long or short), what kind of spin (high spin or low spin

Reptile [31]

Answer:

See explanation

Explanation:

Whether a ligand is strong or weak highly depends on its position in the spectrochemical series. Ligands that are found towards the left hand side of the series are weak field ligands while ions that occur towards the right hand side of the series are strong field ligands. The spectrochemical series is an arrangement of ligands in order of increasing magnitude of crystal field splitting.

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3 years ago

Pleas help with 2 and 4 for brainliest

Snezhnost [94]

mass of pentane : = 30.303 g

moles of Al₂(CO₃)₃ : = 0.147

<h3>Further explanation</h3>

Given

1. Reaction

C₅H₁₂+8O₂→6H₂O+5CO₂.

45.3 g water

2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂

37.2 MgCO₃

Required

mass of pentane

moles of Al₂(CO₃)₃

Solution

1. mol water = 45.3 : 18 g/mol = 2.52

From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :

= 1/6 x mol H₂O

= 1/6 x 2.52

= 0.42

Mass pentane :

= mol x MW

= 0.42 x 72.15 g/mol

= 30.303 g

2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44

mol Al₂(CO₃)₃ :

= 1/3 x mol MgCO₃

= 1/3 x 0.44

= 0.147

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3 years ago