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makvit [3.9K]
3 years ago
14

Electrons, protons, and neutrons are three subatomic particles of an atom. if the atom undergoes a change and becomes a positive

ion, which subatomic particle is lost in this process?
a.neutron
b. proton
c. electron
Chemistry
2 answers:
skelet666 [1.2K]3 years ago
8 0
C. electron.........
il63 [147K]3 years ago
3 0
Id be glad to inform you that it is C. Electron
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Determina el numero de masa para el paladio en la siguiente tabla:*
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The concept of atomic masses we can find that the correct answer is:

       c) 101

The atomic mass or mass number of an element is the sum of its protons plus the neutrons that are in the atomic nucleus, the electrons are not taken into account because they have a mass much lower than the masses of protons and neutrons.

   

In the table they indicate that there are 46 protons and 55 neutrons, therefore

          M = #_ {protons} + #_ {neutrons}

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          M = 101

In conclusion using the concept of atomic masses we find that the correct answer is:

c) 101

Learn more about atomic mass here:

brainly.com/question/1317964

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2 years ago
What kind of bond is present in HCI? (Use the electronegativity values from
Snezhnost [94]
The answer is
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3 years ago
Why helium is duplet ??​
Llana [10]

Answer:

The outermost shell of helium for example is filled with only two electrons. Hydrogen and lithium become stable by acquiring the electronic configuration of the nearest inert gas, which is helium. This is the duplet (or duet) rule.

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.
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Explanation:

Chemical reaction equation for the give decomposition of NH_{3} is as follows:.

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And, initially only NH_{3} is present.

The given data is as follows.

  P_{NH_{3}} = 2.3 atm at equilibrium

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Therefore,

          P_{N_{2}} = \frac{0.69 atm}{3}

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So, P_{NH_{3}} = 2.3 - 2(0.23)

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Now, expression for K_{p} will be as follows.

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                      = \frac{0.23 \times 0.33}{3.39}

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or,           K_{p} = 2.2 \times 10^{-2}

Thus, we can conclude that  the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 2.2 \times 10^{-2}.

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