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inysia [295]
4 years ago
13

Help me asap show work ​

Mathematics
1 answer:
STatiana [176]4 years ago
5 0

We want to find out how much it costs for each pound of feed

For chicken feed 12 divided by 8.40

$1.43 for 1 pound of chicken feed

For goat feed 75 divided by 60

$1.25 for 1 pound of goat feed

For dog feed 50 divided by 37.50

$1.33 for 1 pound of dog feed

For pig feed 80 divided by 62.80

$1.27 for 1 pound of pig feed

When reviewing all the answers per pound for feed, chicken feed is the most expensive per pound.

Hope this helps:)

You might be interested in
A forest covers 46,000 acres. A survey finds that 0.6​% of the forest is​ old-growth trees. How many acres of​ old-growth trees
In-s [12.5K]

Answer: 275 maybe

Step-by-step explanation: i did 46,000 x 0.6% and got 275.

5 0
3 years ago
| 2) through: (-5, -4), perp. to y = -x + 2
schepotkina [342]

Answer:

y=x+1

Step-by-step explanation:

Your generic line will be y= mx+q, so you'll need two condition.

Since it has to be perpendicular to y=(-1)x+2, the product of the slopes needs to be -1, or m(-1)=-1, hence your "generic" becomes y=x+q. Since it has to pass through [/tex](-5;-4), let's put the coordinates in there: (-4)=1(-5)+qq-5=-4q=1

your line becomes y=x+1

8 0
3 years ago
Which of these pairs of points defines a line with slope 0? OA) (1, 4) and (-4,4) OB) (4, 1) and (-4, 4) OC) (-1,4) and (4, -4)
expeople1 [14]

Answer:

4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How to find (a) and (b)?​
rodikova [14]

Answer:

A) Gradient = -3

B) 3y - x = 7

Step-by-step explanation:

The curve has the equation;

y = x³ - 6x² + 9x + 1

We are given the pints it passes through as;

A(2,3) and P(3, 1)

A) to find the gradient, we will find the derivative of the given equation.

Thus;

Gradient = y' = 3x² - 12x + 9

At point A, x = 2. Thus;

Gradient = 3(2²) - 12(2) + 9

Gradient = 12 - 24 + 9

Gradient = -3

B) since the gradient of the tangent = -3, it means the gradient of the normal will be; -1/-3 = 1/3

Thus, equation of the normal to the curve at point A will be;

(y - 3) = ⅓(x - 2)

Multiply both sides by 3 to get;

3y - 9 = x - 2

3y - x = 9 - 2

3y - x = 7

3 0
3 years ago
Give the general form of the equation of the line through (1,2) and is perpendicular to the line passing through (-6,-3)(6,3)
olga nikolaevna [1]

Answer:

4x+3y-10=0

Step-by-step explanation:

first find the gradient of the line that is perpendicular to the line of interest.

y2-y1/x2-x1

3--3/6--6

=3+3/6+6

=9/12

3/4

The gradient of the line of interest is the negative reciprocal of 3/4. Therefore m is -4/3

next, substitute information into

y-y1=m(x-x1)

y-2=-4/3 (x-1)

multiply both sides of equation by 3

3y-6=-4 (x-1)

expand brackets

3y-6=-4x+4

rearrange in general form

4x+3y-10=0

6 0
3 years ago
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