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aliya0001 [1]
3 years ago
14

If you were to measure of liters of gas trapped in a bottle, which of the following would you be describing?

Physics
2 answers:
lina2011 [118]3 years ago
8 0
Your answer is C. Volume
Ratling [72]3 years ago
4 0

Answer: volume

Explanation:

Horsepower is defined as the unit of measurement of the rate at which work is done.

Mass is defined as the amount of matter contained in the body. It is measured in units like gram(g), kilogram (kg) and milligram (mg).

Volume of the gas is defined as the space occupied by a substance. It is expressed in units like cm^3, m^3 , Liters (L) and milliliters (ml)

Pressure of the gas is defined as the force exerted by the particles on the walls of the container. It is expressed in various terms like 'mmHg', 'atm', 'kiloPascals' etc.

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The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground
kati45 [8]

Answer:

The time is 0.90 sec.

Explanation:

Given that,

Height = 4.00 m

We need to calculate the time

Using equation of motion

s = ut-\dfrac{1}{2}(-g)t^2

For free fall, u = 0

t =\sqrt{\dfrac{2s}{g}}

Where, s = distance

g = acceleration due to gravity

t = time

Put the value into the formula

t =\sqrt{\dfrac{2\times4.00}{9.8}}

t= 0.90\ sec

Hence, The time is 0.90 sec.

3 0
3 years ago
What is the purpose of the overrunning clutch in the starter drive?
nadya68 [22]
<span>"prevent the engine from over speeding the armature"
hopes this help :) :D :)</span>
5 0
4 years ago
What is the potential energy of two charges of +4.6 μC and +1.0 μC that are separated by a distance of 10.0 cm?
Artist 52 [7]

Answer:

U = 0.413 J

Explanation:

the potential energy between two charges q1 and q2 is given by the following formula:

U=k\frac{q_1q_2}{r}    (1)

k: Coulomb's constant = 8.98*10^9 NM^2/C^2

q1: first charge = 4.6 μC = 4.6*10^-6 C

q2: second charge = 1.0 μC*10^-6 C

r: distance between charges = 10.0 cm = 0.10 m

You replace the values of all variables in the equation (1):

U=(8.98*10^9Nm^2/C^2)\frac{(4.6*10^{-6}C)(1.0*10^{-6}C)}{0.10m}=0.413\ J

Hence, the energy between charges is 0.413 J

3 0
3 years ago
The distance between two particles is 2 centimeters. If the distance is increased to 4 centimeters, the force will be ?
postnew [5]

Answer:

The new force is 1/4 of the previous force.

Explanation:

Given

Initial\ Distance = 2cm ---- r_1

New\ Distance = 4cm --- r_2

Required

Determine the new force

Let the two particles be q1 and q2.

The initial force F1 is:

F_1 = \frac{kq_1q_2}{r_1^2} --- Coulomb's law

Substitute 2 for r1

F_1 = \frac{kq_1q_2}{2^2}

F_1 = \frac{kq_1q_2}{4}

The new force (F2) is

F_2 = \frac{kq_1q_2}{r_2^2}

Substitute 4 for r2

F_2 = \frac{kq_1q_2}{4^2}

F_2 = \frac{kq_1q_2}{4*4}

F_2 = \frac{1}{4}*\frac{kq_1q_2}{4}

Substitute F_1 = \frac{kq_1q_2}{4}

F_2 = \frac{1}{4}*F_1

F_2 = \frac{F_1}{4}

The new force is 1/4 of the previous force.

3 0
3 years ago
Why is it expensive to bring electricity into urban areas?
motikmotik
Because of the pole and the generator you would have to biuld
8 0
3 years ago
Read 2 more answers
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