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aliya0001 [1]
3 years ago
14

If you were to measure of liters of gas trapped in a bottle, which of the following would you be describing?

Physics
2 answers:
lina2011 [118]3 years ago
8 0
Your answer is C. Volume
Ratling [72]3 years ago
4 0

Answer: volume

Explanation:

Horsepower is defined as the unit of measurement of the rate at which work is done.

Mass is defined as the amount of matter contained in the body. It is measured in units like gram(g), kilogram (kg) and milligram (mg).

Volume of the gas is defined as the space occupied by a substance. It is expressed in units like cm^3, m^3 , Liters (L) and milliliters (ml)

Pressure of the gas is defined as the force exerted by the particles on the walls of the container. It is expressed in various terms like 'mmHg', 'atm', 'kiloPascals' etc.

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(Mass vs. Weight) HELP PLZ!!
Lina20 [59]

\huge \boxed { \sf{Answers}}

  • c. The weight of an object on the moon will be the same as its weight on Earth. It is false because the weight of an on the moon will be 1/6 th times its weight on Earth.
  • d. The weight of an object is its mass multiplied by the force of gravity. The statement is false because the formula of weight is mass × acceleration due to gravity, not force of gravity.
  • e. The mass and weight of an object are the same thing. The statement is false because mass means a body of matter. While weight of an object is its mass multiplied by the force of gravity.
  • f. The mass of an object is the force of gravity acting upon an object. It is false because it will be the weight of the object not mass.
  • So, the answers are c, d, e and f.

Hope you could understand.

If you have any query, feel free to ask.

7 0
2 years ago
An 8-passenger Learjet has a force of gravity of 6.6x10^4 [down] acting on it as it travels at a constant velocity of 6.4x10^2 k
IgorC [24]
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7 0
3 years ago
What is one latitude where there is no continental barriers?
AveGali [126]
The equator has no continental borders.
5 0
3 years ago
Read 2 more answers
A 25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. The
Alex787 [66]

Answer:

h=18.05 cm

Explanation:

Given that

m= 25 kg

K= 1300 N/m

x=26.4 cm

θ= 19.5 ∘

When the block just leave the spring then the speed of block = v m/s

From energy conservation

\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2

Kx^2=mv^2

v=\sqrt{\dfrac{kx^2}{m}}

By putting the values

v=\sqrt{\dfrac{kx^2}{m}}

v=\sqrt{\dfrac{1300\times 0.264^2}{25}}

v=1.9 m/s

When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

V_f^2=V_i^2-2gh

By putting the values

0^2=1.9^2-2\times 10\times h

h=0.1805 m

h=18.05 cm

4 0
3 years ago
Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.
padilas [110]

Explanation:

We have,

Semimajor axis is 4\times 10^{12}\ m

It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

T^2=\dfrac{4\pi ^2}{GM}a^3

G is universal gravitational constant

M is solar mass

Plugging all the values,

T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s

Since,

1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}

So, the orbital period of a dwarf planet is 138.52 years.

3 0
3 years ago
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