HELP!!!!

What two factors affect the speed of a sound wave as it travels through a medium ?

iragen [17]

The material that makes up the medium such as air or water and the temperature.

6 0

3 years ago

A cave explorer travels 3.00 m eastward, then 6.50 m northward, and finally 12.0 m westward. Find the magnitude of the net displ

mina [271]

<span>3 meters east and 15 meters west evens out to 12 meters west. the answer is 12 meters west
</span>

7 0

3 years ago

A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.

lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

(c) 920.84 A

Solution:

As per the question:

Voltage at primary, $V_{p} = 120\ V$ (rms voltage)

Voltage at secondary, $V_{s} = 13000\ V$ (rms voltage)

Current in the secondary, $I_{s} = 8.50\ mA$

Now,

(a) The ratio of secondary to primary turns is given by the relation:

$\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}$

where

$N_{p}$ = No. of turns in primary

$N_{s}$ = No. of turns in secondary

$\frac{N_{s}}{N_{p}} = \frac{13000}{120}$ ≈ 108

(b) The power supplied to the line is given by:

Power, P = $V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW$

(c) The current rating that the fuse should have is given by:

$\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}$

$\frac{13000}{120} = \frac{I_{p}}{8.50}$

$I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A$

6 0

3 years ago

Hey, I need help with my homework.

Anna11 [10]

We have that the Average Force is given

Avg F=2.0488N

From the question we are told

Masses=

0.10

0.25

0.40

0.50

0.60

0.75

1

1.5

2

Accelerations

9.5

4.2

2.3

2.1

1.7

1.3

1.1

0.7

0.5

Generally the equation for the Mean is mathematically given as

For Mass

$X=\frac{\sum x}{n}\\\\X=\frac{0.10 +0.25+0.40+0.50+0.60+0.75+1+1.5+2}{9}\\\\X=0.788g$

For Acceleration

$X'=\frac{\sum x}{n}\\\\X'=\frac{9.5+4.2+2.3+2.1+1.7+1.3+1.1+0.7+0.5}{9}\\\\X'=2.6m/s^2$

Since Average Acceleration and mass are found above

Therefore

The Average Force is given as

Generally the equation for the Average Force is mathematically given as

$Avg F=Avg m *Avg a\\\\Avg F=0.788*2.6\\\\Avg F=2.0488$

For more information on this visit

brainly.com/question/17871636

6 0

3 years ago

You have a stopped pipe of adjustable length close to a taut 62.0-cm, 7.25-g wire under a tension of 3910 N . You want to adjust

Ber [7]

Answer:

L = 6 cm

Explanation:

Second overtone of the wire is same as third harmonic

so its frequency is given as

$f = \frac{3}{2L}\sqrt{\frac{T}{\mu}}$

here we know that

$\mu = \frac{M}{L}$

$\mu = \frac{7.25 \times 10^{-3}}{0.62}$

$\mu = 0.0117 kg/m$

now we have

$f = \frac{3}{2\times 0.62}\sqrt{\frac{3910}{0.0117}}$

$f = 1398.6 Hz$

Now fundamental frequency of sound in a pipe is given as

$f = \frac{v}{4L}$

$1398.6 = \frac{340}{4L}$

$L = 0.06 m$

$L = 6 cm$

7 0

3 years ago