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Tanya [424]
3 years ago
8

A force of 9 pounds stretches a spring 1 foot. A mass weighing 6.4 pounds is attached to the spring, and the system is then imme

rsed in a medium that offers a damping force numerically equal to 1.2 times the instantaneous velocity. Find the equation of motion If the mass is initially released from rest from a point 1 foot above the equilibrium position.
Physics
1 answer:
mart [117]3 years ago
7 0

Answer:

\frac{d^2x}{dt^2}+\frac{\beta}{m}\frac{dx}{dt}+\frac{k}{m}x=0

Explanation:

let m be the mass attached, let k be the spring constant and let \beta be the positive damping constant.

-By Newton's second law:

m\frac{d^2x}{dt^2}=-kx-\beta \frac{dx}{dt}

where x(t) is the displacement from equilibrium position. The equation can be transformed into:

\frac{d^2x}{dt^2}+\frac{\beta}{m}\frac{dx}{dt}+\frac{k}{m}x=0  shich is the equation of motion.

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Work = (force) x (distance)

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Friction eats up    (27N) x (4m) = 108 joules of that energy,
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The remaining    (160J - 108J) = 52 joules of energy moves the box.

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What is energy? Where does it come from? What does it do? Explain in 5 or more sentences please! :)
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Answer:

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Explanation:

Energy is defined as the ability to do work and can be in various forms such as kinetic energy, potential energy, thermal, chemical, electrical energy etc.

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4 0
2 years ago
Which type of rock would form from a lava following a volcanic eruption
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What is the net force acting on Hector and the toboggan?
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A single conservative force acts on a 5.30-kg particle within a system due to its interaction with the rest of the system. The e
cupoosta [38]

Answer:

Given that

m = 5.3 kg

Fx = 2x + 4

We know that work done by force F given as

w= ∫ F. dx

a)

Given that x=1.08 m to x=6.5 m

Fx = 2x + 4

w= ∫ F. dx

w=\int_{1.08}^{6.5}(2x+4) .dx

w=\left [x^2+4x \right ]_{1.08}^{6.5}

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b)

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c)

We know that form work power energy theorem

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