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Anni [7]
2 years ago
7

Help me solve this please

Mathematics
1 answer:
stealth61 [152]2 years ago
8 0

Answer:

the answer is 0.7692

Step-by-step explanation:

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A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i
Ray Of Light [21]

Answer:


Step-by-step explanation:

<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

                 AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

<em>                    </em><em><u>equal. </u></em>

<em><u>Solution</u></em>:  Now, In ΔADM and ΔADN

                 ∠MAD=∠NAD     ...(1) (∵Given)

                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


7 0
3 years ago
Help due by 11 it 10 :55
belka [17]

Answer: 0.11

Step-by-step explanation: (2/3) / 6 = 0.11

4 0
3 years ago
Read 2 more answers
Determine the critical value or values for a one-mean z-test at the 1% significance level if the hypothesis test is right-tailed
kifflom [539]

Answer:

We need to conduct a hypothesis in order to determine if the mean is greater than specified value, the system of hypothesis would be:      

Null hypothesis:\mu \leq \mu_o      

Alternative hypothesis:\mu > \mu_o      

For this case the significance is 1%. So we need to find a critical value in the normal standard distribution who accumulates 0.99 of the area in the left and 0.01 in the right and for this case this critical value is:

z_{crit}= 2.326

Step-by-step explanation:

Notation

\bar X represent the sample mean

\sigma represent the standard deviation for the population      

n= sample size      

\mu_o represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)      

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is greater than specified value, the system of hypothesis would be:      

Null hypothesis:\mu \leq \mu_o      

Alternative hypothesis:\mu > \mu_o      

For this case the significance is 1%. So we need to find a critical value in the normal standard distribution who accumulates 0.99 of the area in the left and 0.01 in the right and for this case this critical value is:

z_{crit}= 2.326

3 0
3 years ago
Which expression is equivalent to 7 (x + 4)?
aalyn [17]

Answer:

7 times 5x

Step-by-step explanation:

4 plus x and x has value

3 0
3 years ago
Read 2 more answers
Niklas takes a dose of 252525 micrograms (\text{mcg})(mcg)left parenthesis, m, c, g, right parenthesis of a certain supplement e
11Alexandr11 [23.1K]

Niklas takes a dose of 25 micrograms of a certain supplement each day. The supplement has a half life of 4 hours, meaning that 1/64 of the supplement remains in the body after each day. How much of the supplement is in Niklas's body immediately after the 12th dose? Round your final answer to the nearest hundredth.

Answer:

The amount of the supplement in Niklas body immediately after the 12th dose is 430 micrograms to the nearest hundreth

Step-by-step explanation:

Half life is the time required for an element to decay into half of its initial size.

Given that :

The supplement has a half life of 4 hours, this implies that  it decay to half of its size every 4 hours.

∴ there are 6 stages of division in a day.

i.e

\dfrac{1}{2}*\dfrac{1}{2}*\dfrac{1}{2}*\dfrac{1}{2}*\dfrac{1}{2}*\dfrac{1}{2} =\dfrac{1}{64}

The amount of the supplement in Niklas body after the first dose (first day) can be calculated as:

=  \dfrac{1}{64} × 25

= 0.390625 micrograms

It is said that he used the supplement daily for 12 days (12th dose),

As such ; we can estimate the amount of the supplement that is in his body immediately after the 12th dose; which is calculated as:

amount in his body per day × number of period for complete decay

= 0.390625 × 11

= 4.296875

≅4.30 micrograms

= 430 micrograms to the nearest hundreth

The amount of the supplement in Niklas body immediately after the 12th dose is 430 micrograms to the nearest hundreth

3 0
3 years ago
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