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jeyben [28]
3 years ago
14

A person suffering from hyponatremia has which of the following?a. Too little sodium in the bloodb. Too much sodium in the blood

c. Equal concentrations of sodium and water in the bloodd. Too little water in the blood
Physics
1 answer:
Art [367]3 years ago
6 0

A person suffering from hyponatremia has too little sodium in the bloodstream. This condition appears when their is more amount of water as compared to solute. it is commonly caused by diarrhea, heart failure and liver disease. Person suffering from this condition must reduce the intake of water.

So the correct choice is

a. Too little sodium in the bloodstream.

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Mr. Mehta cut several 275-centimeter lengths of wallpaper to put in his
mihalych1998 [28]

Answer:

2.75 meters.

Explanation:

1 meter = 100 centimeters.

There are 275 centimeters.

275/100=2.75

So, each piece of wallpaper was 2.75 meters long.

6 0
3 years ago
Give examples of not useful high friction
Tatiana [17]
Friction can be bad by being too strong or too weak. 

<span>Sometimes, when it is too strong, it decreases efficiency since some energy is wasted and turns to heat. Friction can also d</span><span>amage equipment/objects like when you slide it on the floor.
</span>
When friction is too weak, like for instance when there is black ice- our center of gravity is displaced too quickly and we can fall. Likewise, if there is a lot of slush on the ground, cars can slip and slide.
6 0
3 years ago
Technician A says that the device that controls shift points on an automatic transmission is the valve body. Technician B says t
alexira [117]

Answer: Technician B only

Explanation:

What actually controls the shifting in a automatic transmission is the vehicle's internal computer that helps shift the gears automatically. This includes a Control Module that adjusts the current provided to solenoids inside to control the gears The hydraulic system is used to select gears dependent on the transmission fluid's pressure applied.

3 0
3 years ago
A 2.00-kg rock has a horizontal velocity of magnitude 12.0 m&gt;s when it is at point P in Fig. E10.35. (a) At this instant, wha
zaharov [31]

Answer:

(A) L = 115.3kgm²/s

(B) dL/dt = 94.1kgm²/s²

Explanation:

The magnitude of the angular momentum of the rock is given by the foemula

L = mvrSinθ

We have been given θ = 36.9°, m = 2.0kg, v = 12.0m/s and r = 8.0m.

Therefore L = 2.00 × 12 × 8.0 × Sin 36.9° =

115.3 kgm²/s

(B) The magnitude of the rate of angular change in momentum is given by

dL /dt = d(mvrSinθ)/dt = mgrSinθ = 2.00 × 9.8 × 8.0× Sin36.9 = 94.1kgm²/s²

7 0
3 years ago
What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s
mars1129 [50]

Answer:

\mu = \frac{1}{2tan\theta}

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

\mu N_1 = N_2

by vertical force balance we have

N_1 = mg

now by torque balance about contact point on ground we will have

mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)

so we will have

N_2 = \frac{mg}{2tan\theta}

now from first equation we have

\mu (mg) = \frac{mg}{2tan\theta}

\mu = \frac{1}{2tan\theta}

3 0
3 years ago
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