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3 years ago

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Un montacargas hidráulico es utilizado para levantar cajas con un peso de 1500 newtons sobre una superficie de 20 cm al cuadrado

. ¿Cuál es la fuerza que se aplica sobre una base de 2 cm al cuadrado?

1 answer:

saveliy_v [14]3 years ago

3 0

Answer:

150 N

Explanation:

The question says that, "A hydraulic forklift is used to lift boxes with a weight of 1500 newtons over a surface of 20 cm squared. What is the force applied to a base of 2 cm squared?"

Given that,

Force applied, F₁ = 1500 N

Area, A₁ = 20 cm²

We need to find the force applied to a base of 2 cm². Using Pascal's law to find it such that,

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{1500\times 2}{20}\\\\F_2=150\ N$

So, the required weight is 150 N.

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Microwave ovens emit microwave energy with a wavelength of 12.1 cm. What is the energy of exactly one photon of this microwave r

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Answer:

$1.64\cdot 10^{-24}J$

Explanation:

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For the microwave photons in this problem,

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A child whose weight is 287 N slides down a 7.20 m playground slide that makes an angle of 31.0Â° with the horizontal. The coeff

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Answer:

a

$H =212.6 \ J$

b

$v = 7.647 \ m/s$

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From the question we are told that

The child's weight is $W_c = 287 \ N$

The length of the sliding surface of the playground is $L = 7.20 \ m$

The coefficient of friction is $\mu = 0.120$

The angle is $\theta = 31.0 ^o$

The initial speed is $u = 0.559 \ m/s$

Generally the normal force acting on the child is mathematically represented as

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Note $m * g = W_c$

Generally the frictional force between the slide and the child is

$F_f = \mu * mg * cos \theta$

Generally the resultant force acting on the child due to her weight and the frictional force is mathematically represented as

$F =m* g sin(\theta) - F_f$

Here F is the resultant force and it is represented as $F = ma$

=> $ma = m* g sin(31.0) - \mu * mg * cos (31.0)$

=> $a = g sin(31.0)- \mu * g * cos (31.0)$

=> $a = 9.8 * sin(31.0) - 0.120 * 9.8 * cos (31.0)$

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So

$F_f = 0.120 * 287 * cos (31.0)$

=> $F_f = 29.52 \ N$

Generally the heat energy generated by the frictional force which equivalent tot the workdone by the frictional force is mathematically represented as

$H = F_f * L$

=> $H = 29.52 * 7.2$

=> $H =212.6 \ J$

Generally from kinematic equation we have that

$v^2 = u^2 + 2as$

=> $v^2 = 0.559^2 + 2 * 4.039 * 7.2$

=> $v = \sqrt{0.559^2 + 2 * 4.039 * 7.2}$

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Answer:

Explanation:

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