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White raven [17]
3 years ago
15

A gas is confined in a cylinder with a piston. What happens when work is done on the gas.

Physics
2 answers:
goblinko [34]3 years ago
5 0
It combusts in to a vapor

yanalaym [24]3 years ago
3 0

The correct answer is:

The volume of the gas decreases

Explanation:

As the piston is forced down work is done on the gas. The force exercised by the gas pressure on the piston is in the adverse direction of the motion of the piston. The volume of the space the gas absorbs decreases. When we let go of the piston the gas extends. The force exercised by the gas is in the similar direction as the motion of the piston and work is done by the system.

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The flow rate over Niagara falls is 84,760 cfs (cubic feet per second), and the drop from top to bottom is 167 feet. If this flo
jekas [21]

To develop this problem we will calculate the volume from the given flow (volume per unit of time). This process will be accompanied by transforming the units given in the International system.

Through the density-volume-mass ratio, we will calculate the mass. Finally we will proceed to calculate the total power generated.

1 feet = 0.3048 m

\dot{V} = 84760ft^3/s

\dot{V} = 84760ft^3/s (\frac{(0.3058m)^3}{(1ft)^3})

\dot{V} = 2400m^3/s \text{and the Volume each second is } V= 2400m^3

Now the mass of water falling down each second would be

\rho = \frac{m}{V} \rightarrow m = \rho V

m = (1000kg/m^3)(2400m^3)

m = 2.4*10^6kg

Now Height in meters is

h = 167 ft (\frac{(0.3058m)}{(1ft)})

h= 50.9 m

The power produced is equivalent to the work done by gravity over a certain time. At this case that can be expressed as,

P = \frac{W}{t}\\P = \frac{F*h}{t}\\P = \frac{mgh}{t}\\P = \frac{2.4*10^6*9.8*50.9}{1}\\P = 1.197*10^9 Watts

The power of Niagara Falls then would be 1.197GW while the power generated by the Three Gorges Dam is  22,500 MW. This indicates that the Niagara Falls, if it were a dam that covered 100% of the fluid it carries, would exceed the production of the dam in China by thousands.

8 0
4 years ago
In a collision, the human body will strike the seatbelt, steering wheel, dash or windshield at? Group of answer choices only 10
Alla [95]

Answer:

isn't this kinda like math

Explanation:

3 0
3 years ago
Read 2 more answers
What are the coordinates of the point that is 1/5 of the way from A(-7,-4) to B(3, 6)?
Olegator [25]

Answer:

coordinate will be

r = (1.33,4.33)

Explanation:

As we know that if a point will divide two given coordinates in m : n ratio

then in that case the point is given as

x = \frac{mx_1 + nx_2}{m+n}

y = \frac{my_1 + ny_2}{m+n}

here we know that two points are

(-7, -4) and (3, 6)

and the ratio is given as 1 : 5

now from above formula we will have

x = \frac{1(-7) + 5(3)}{1 + 5} = 1.33

y = \frac{1(-4) + 5(6)}{1 + 5} = 4.33

so coordinate will be

r = (1.33, 4.33)

7 0
4 years ago
A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of
bekas [8.4K]

Answer:

The magnitude of the induced Emf is 0.003371V

Explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the induced EMF= B L v

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

8 0
4 years ago
What is the final velocity of a drag racer that has constant acceleration and finishes a
Svetradugi [14.3K]

Answer:

120 mph

Explanation:

Given:

Δx = 0.25 mi

v₀ = 0 mi/s

t = 15 s

Find: v

Δx = ½ (v + v₀) t

0.25 mi = ½ (v + 0 mi/s) (15 s)

v = 0.0333 mi/s

v = 120 mi/h

8 0
3 years ago
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