Which temperature is warmer than the freezing point of water

A weightlifter can exert an upward force of 3750 N. If a dumbbell has a mass of 225 kg, what is the maximum number of dumbbells

MrRissso [65]

Answer:

10 dumbbells

Explanation:

First we need to calculate the gravity on the moon.

0.166 x 9.8 m/s² = 1.627 m/s² (the gravity is 0.166 times the Earth's gravity)

Taking this acceleration due to gravity, and multiplying it by the mass of a single dumbbell.

F = m x a

F = (225 kg) x (1.627 m/s²)

F = 366.075 N (the amount of force exerted by the dumbbell)

Taking the weightlifter's total upward force and dividing it by the force exerted by one dumbbell, we can calculate the amount of dumbbells that can be carried.

(3750 N) / (366.075 N)

= 10.24 dumbbells (but since there cannot be a fraction of a dumbbell, the answer is <u>10 dumbbells</u>).

6 0

3 years ago

Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. how long will you measure it to be if

Fantom [35]

Calculate the length of a spaceship as follows:

l = l₀√1 - v²/c²

=(400 m)√1 - (0.75c)2 c²

=264.575m.

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Starships, also known as star cruisers, starships, spacecraft, or simply starships or ships, were vessels designed specifically for interstellar travel between star systems.

For clients in the Spaceship Index portfolio, the situation is a little different. The Spaceship Index portfolio consists of approximately 100 of his ASX-listed companies with the largest market capitalization and approximately 100 global companies with the largest market capitalization.

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8 0

1 year ago

1. The electromagnetic waves described in the reading are different in which two ways:

Kipish [7]

Answer:

D is the answer

Explanation:

But do u know if im right test it out then surprise

8 0

2 years ago

Find its moment of inertia about an axis perpendicular to its plane and passing through the midpoint of the line connecting its

antoniya [11.8K]

A) Moment of inertia about an axis passing through the point where the two segments meet : $I_A=\frac{1}{12} M L^2$

B) Moment of inertia passing through the point where the midpoint of the line connects to its two ends: $I x=\frac{1}{3} M L^2$

What is Moment of inertia?

The term "moment of inertia" refers to a physical quantity that quantifies a body's resistance to having its speed of rotation along an axis changed by the application of a torque (turning force). The axis might be internal or exterior, fixed or not.

A) The moment of inertia about an axis passing through the point where the two segments meet is $I_A=\frac{1}{12} M L^2$ given that the rod is bent at the center and distance from all the points to the axis remains the same, the moment of inertia about the center will remain the same.

B) Determine the moment of inertia about an axis passing through the point midpoint of the line which connects the two ends

First step: determine the distance between the ends ( d )

After applying Pythagoras theorem $\mathrm{d}=\frac{\sqrt{2}}{2} L$

Next step : determine distance between the two axis $(\mathrm{x})$

After applying Pythagoras theorem

$\mathrm{x}=\frac{\sqrt{2}}{4} L$$$

Final step : Calculate the value of $\mathrm{I}_{\mathrm{x}}$

applying Parallel Axis Theorem

$I_x=I_8+M x^2$

$\begin{aligned}& =\frac{1}{12} M L^2+\frac{1}{4} M L^2 \\& \therefore \quad I x=\frac{1}{3} M L^2 \\&\end{aligned}$

Hence we can conclude that Moment of inertia about an axis passing through the point where the two segments meet: $I_A=\frac{1}{12} M L^2$ , Moment of inertia passing through the point where the midpoint of the line connects its two ends: $I x=\frac{1}{3} M L^2$

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5 0

1 year ago

Finish A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?

Lina20 [59]

Answer:

$\boxed {\boxed {\sf 6 \ meters}}$

Explanation:

Work is the product of force and distance.

$W=F*d$

We know that 96 Joules of work were done and a 16 Newton force was applied to the object.

W= 96 J
F= 16 N

Substitute the values into the formula.

$96 \ J= 16 \ N * d$

First, let's convert the units. This will make cancelling units easier later in the problem. 1 Joule (J) is equal to 1 Newton meter (N*m), so the work of 96 Joules equals 96 Newton meters.

$96 \ N*m= 16 \ N * d$

Now, solve for distance by isolating the variable, d. It is being multiplied by 16 Newtons and the inverse of multiplication is division. Divide both sides of the equation by 16 N.

$\frac {96 \ N*m}{16 \ N}= \frac{16 \ N *d}{16 \ N}$

$\frac {96 \ N*m}{16 \ N}=d$

The units of Newtons cancel.

$\frac {96}{16} \ m = d$

$6 \ m = d$

The object moved a distance of <u>6 meters.</u>

3 0

2 years ago