Answer:
<u>Inelastic collision:</u>
A collision in which there is a loss of Kinetic Energy due to internal friction of the bodies colliding.
<u>Characteristics of an inelastic collision:</u>
- <em>the momentum of the system is conserved</em>
- <em>the momentum of the system is conservedloss of kinetic energy</em><u> </u>
<em>I</em><em>n</em><em> </em><em>a perfectly elastic collision</em><em>, the two bodies </em><em>that</em><em> </em><em>collide with each other stick together.</em>
<u>Elastic </u><u>collision</u><u>:</u>
A collision in which the kinetic energy of the two bodies, before and after the collision, remains the same.
<u>Characteristic</u><u>s</u><u> </u><u>of</u><u> </u><u>elastic</u><u> </u><u>collision</u><u>:</u>
- <em>the</em><em> </em><em>momentum</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>system</em><em> </em><em>is</em><em> </em><em>conserved</em>
- <em>no</em><em> </em><em>loss</em><em> </em><em>o</em><em>f</em><em> </em><em>kinetic</em><em> </em><em>energy</em>
In everyday life, no collision is perfectly elastic.
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ANSWER:
<u>Given examples:</u>
- Two cars colliding with each other form an example of inelastic collision.
<u>Reason:</u>
<em>(</em><em>T</em><em>hey</em><em> </em><em>lose</em><em> </em><em>kinetic</em><em> </em><em>energy</em><em> </em><em>and</em><em> </em><em>come</em><em> </em><em>to</em><em> </em><em>a</em><em> </em><em>stop</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>collision</em><em>.</em><em>)</em>
- A ball bouncing after colliding with a surface is an example of elastic collision
<u>Reason:</u>
<em>(a very less amount of kinetic energy is lost)</em>
THE ANSWER FOR UR QUESTION IS
WHICH COUNTRY OR REGION IS COAL RICH AND OIL POOR
ANS:- UNITED STATES IS THE COUNTRY WHICH IS COAL RICH AND OIL POOR
HOPE THIS HELPS!!!
^_^ HAPPY TO HELP U ^_^
I found that it was: Distance to stars, Brightness of stars and Composition of stars. Hope this helps!
Answer:
1.4 m/s
Explanation:
The final velocity of the ball can be found by using the following SUVAT equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance travelled
In this problem,
u = 4.0 m/s
d = 14 m
a = -0.50 m/s^2
Solving the equation for v,
Answer:
q=471.19kj.kg
Explanation:water constant volume = C
First state
Quantity X1=1
Pressure=1 bar
Second state
T2=400C
Required heat transferred q in kj.kg
Assumption:
System is at equilibrium
Kinetic and Potential energy are neglected
Therefore, from 1st law of thermodynamics q - w=∆u. . . . 1
From steam table A
U1=Ug=2553.6kj.kg
U2=Vg=1625m³.kg
V1=V2=4625m³.kg
From steam Table B
Px= 7 bar
Vx=4667kj.kg
Ux=3026.6kj.kg
Py= 10 bar
Vy= 3066kj.kg
Uy=2957.5kj.kg
Assuming a Linear interpolation
Ux-V2/Ux-Vy=Vx-U2/Ux-Vy
U2 =Vx-{vx-vy}× vx-v2/Ux-Vy
U2 = 3026.6 - (3026.6-2957.3)× 4667-4625/4667-3066
=3024.79kj.kg
Therefore, from q-w=∆u
q=3024.79-253.6
=471.19kj.kg
Where u = internal energy
V= specific volume