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Elena L [17]
3 years ago
13

A 100 kg cart accelerates at 0.50 meters per second squared west as the horse exerts a force of 60 newtons west on the cart what

is the magnitude of the force that the car exerts on the horse
Physics
1 answer:
mojhsa [17]3 years ago
5 0
<span>Newton's third law of motion (also known as lar of action-reaction) states that when an object A exertes a force on another object B, object B also exerts a force on object A equal and opposite to the first force. If we apply the law to this problem, we can say that the force exerted by the car on the horse is equal to the force exerted by the horse on the car, so its magnitude is 60 N.</span>
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A proton and an electron are released from rest, with only the electrostatic force acting. Which of the following statements mus
Anit [1.1K]

Answer:

Their kinetic energy will increase but potential energy will decrease.

Explanation:

Given that

Initial velocities of electron and proton is zero.

We know that ,electron have negative charge and proton have positive charge it means that they will attract to each other.We know that opposite charge attract to each other and same charge repels to each other.

It means that the velocities of proton and electron will increase and that leads to increase in the kinetic energy of proton and electron.

We know that potential energy U

U\alpha -\dfrac{1}{r}

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5 0
3 years ago
A 2-way light bulb for a 110 V lamp has filament that uses power at a rate of 50.0 W. What is the resistance of the filament?
Novosadov [1.4K]

Answer:r=242ohms

Explanation:

Power(p)=50w

Volt(v)=110v

Resistance(r)=?

Power(p)=((volt)^2)/(resistance(r))

50=110^2/r

Cross product

50xr=110^2

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3 0
3 years ago
Two vectors have magnitudes of 25 and 12. Which of the following is the only possible resultant for these vectors? A.25 B.12 C.4
Westkost [7]

Answer:

Step 1: Draw the vectors[Ref. Fig.]

Consider there are two vectors A and B such that B is perpendicular to the resultant R

Since the resultant is perpendicular to vector B we will get a right-angled triangle

Step 2: Equation formation

From the triangle

                ∣A∣2=∣B∣2+∣R∣2                                             ....(1)

Given ,    ∣R∣=∣A+B∣=12                                            ....(2)   

                ∣A∣+∣B∣=18                                                     ....(3)  

Step 3: Solving Equations

Equation (3) and (1)⇒     ∣A∣2=(18−∣A∣)2+(12)2

                                    ⇒  ∣A∣2=182+∣A∣2−2×18∣A∣+

Explanation:

hope it helps

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