Given data
*The given mass of the pendulum is m = 3 kg
*The given height is h = 0.3 m
The formula for the maximum speed of the pendulum is given as
![v_{\max }=\sqrt[]{2gh}](https://tex.z-dn.net/?f=v_%7B%5Cmax%20%7D%3D%5Csqrt%5B%5D%7B2gh%7D)
*Here g is the acceleration due to the gravity
Substitute the values in the above expression as
![\begin{gathered} v_{\max }=\sqrt[]{2\times9.8\times0.3} \\ =2.42\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20v_%7B%5Cmax%20%7D%3D%5Csqrt%5B%5D%7B2%5Ctimes9.8%5Ctimes0.3%7D%20%5C%5C%20%3D2.42%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
Hence, the maximum speed of the pendulum is 2.42 m/s
The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.
To find the answer, we have to know more about the ideal diode.
<h3>
What is an ideal diode?</h3>
- A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another.
- A semiconductor diode is the kind of diode that is used the most commonly.
- It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.
<h3>How to find the current in ideal diode?</h3>
- Here we have given with the values,
- We have the expression for current in mA of the ideal diode with forward biased voltage drop as,
Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.
Learn more about the ideal diode here:
brainly.com/question/14988926
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The correct answer to this problem is C
The frequency of the wave is determined as 7.96 Hz.
<h3>
Frequency of the wave</h3>
The frequency of the wave is calculated as follows;
y = A sin(ωt - kx)
where;
- A is amplitude of the wave
- ω is angular speed of the wave
ω = 2πf
f = ω/2π
f = (50)/(2π)
f = 7.96 Hz
Thus, the frequency of the wave is determined as 7.96 Hz.
Learn more about frequency of waves here: brainly.com/question/6297363
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