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swat32
4 years ago
7

QUESTION 5

Mathematics
1 answer:
Grace [21]4 years ago
7 0

Answer:

the anwer is D.8V2m to youre question

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Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.
tester [92]

Given:

Polynomial is 3x^2+15x-56.

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

3x^2+15x-56+(x-8)^2

=3x^2+15x-56+x^2-2(x)(8)+8^2    [\because (a-b)^2=a^2-2ab+b^2]

=3x^2+15x-56+x^2-16x+64

On combining like terms, we get

=(3x^2+x^2)+(15x-16x)+(-56+64)

=4x^2-x+8

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is 4x^2-x+8.

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3 years ago
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8 0
3 years ago
What is the sum of 1 - 0.5 + 899
I am Lyosha [343]

Answer:

899.5

Step-by-step explanation:

8 0
3 years ago
Find the second derivative of 2x^3-3y^2=8​
Umnica [9.8K]

Answer:

\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

Step-by-step explanation:

<u>Find the first implicit derivative using implicit differentiation</u>

<u />2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}

<u>Use the substitution of dy/dx to find the second derivative (d²y/dx²)</u>

<u />\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

5 0
3 years ago
How do I solve -8&gt;16?
tatuchka [14]

Answer:

18 is greater than 16

Step-by-step explanation:

4 0
3 years ago
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