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3 years ago

14

If a ball is rolling in a straight line and you push it to the right its velocity will to the right

1 answer:

Keith_Richards [23]3 years ago

4 0

The answer would be "velocity will stay in the same direction." Since the ball is going in the same the ball is still going straight but just right. Many people get confused over velocity and speed, speed it the average amount on how fast a object is going and velocity is the amount of force a object has when it has speed. So, in this case since how the ball is going straight but just right it would stay in the same direction.

Hope this helps!

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The force of gravity on Mercury is less than the Earth because:

Vinvika [58]

Mercury has less mass than earth. So the answer is B

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A scuba diver at 70 m below the surface of a lake, where the temperature is 4 degrees C, releases an air bubble with a volume of

posledela

Answer:

121.3 cm^3

Explanation:

P1 = Po + 70 m water pressure (at a depth)

P2 = Po (at the surface)

T1 = 4°C = 273 + 4 = 277 K

V1 = 14 cm^3

T2 = 23 °C = 273 + 23 = 300 K

Let the volume of bubble at the surface of the lake is V2.

Density of water, d = 1000 kg/m^3

Po = atmospheric pressure = 10^5 N/m^2

P1 = 10^5 + 70 x 1000 x 10 = 8 x 10^5 N/m^2

Use the ideal gas equation

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

By substituting the values, we get

$\frac{8\times 10^5\times 14}{277}=\frac{10^{5} \timesV_{2}}{300}$

V2 = 121.3 cm^3

Thus, the volume of bubble at the surface of lake is 121.3 cm^3.

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3 years ago

If the heating curve is reversed, what would best describe the boiling point?

Slav-nsk [51]

Answer:

point of condensation

Explanation:

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In 1958 a large earthquake in Alaska produced a tsunami. What was the approximate height of the tsunami?

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Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the

saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

$R=\alpha \frac{l}{s}$

Were:

R is resistance

$\alpha$ is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area ( $s=\pi r^{2}$ ).

So if the lenght and radius are doubled, the equation goes as follows:

$R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }$

So finally because the circular area is a square function, the resulting equation is half of the one before.

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3 years ago