All categories

2 years ago

If a ball is rolling in a straight line and you push it to the right its velocity will to the right

1 answer:

4 0

The answer would be "velocity will stay in the same direction." Since the ball is going in the same the ball is still going straight but just right. Many people get confused over velocity and speed, speed it the average amount on how fast a object is going and velocity is the amount of force a object has when it has speed. So, in this case since how the ball is going straight but just right it would stay in the same direction.

Hope this helps!

You might be interested in

A 6.7kg object moves with a velocity of 8m/s. What's its kinetic energy?

Snezhnost [94]

Given parameters:

Mass of object = 6.7kg

Velocity = 8m/s

Unknown parameter:

Kinetic energy = ?

Energy is defined as the ability to do work. There are two forms of energy;

Kinetic and potential energy.

Kinetic energy is the energy due to the motion of a body. Whereas, potential energy is the energy due to the position of a body usually at rest.

Kinetic energy is mathematically expressed as;

Kinetic energy = $\frac{1}{2} m v^{2}$

where m is the mass of the body

v is the velocity of the body

Since we have been given both mass and velocity, input the parameter to solve for the unknown;

Kinetic energy = $\frac{1}{2}$ x 6.7 x 8² = 214.4‬J

So the kinetic energy of the body is 214.4‬J

3 0

2 years ago

A person standing a certain distance from four identical loudspeakers is hearing a sound level intensity of 125 dB. What sound l

DENIUS [597]

Answer:

$\mathbf{\beta = 123.75 \ dB}$

Explanation:

From the question, using the expression:

$125 \ dB = 10 \ log (\dfrac{I}{I_o})$

where;

$I_o = 10^{-12} \ W/m^2$

$I = 10^{12.5} \times 10^{-12} \ W/m^2$

$I = 3.162 \ W/m^2$

This is a combined intensity of 4 speakers.

Thus, the intensity of 3 speakers = $\dfrac{3.162\times 3}{4}$

= 2.372 W/m²

Thus;

$\beta = 10 \ log ( \dfrac{2.372}{10^{-12}} ) \ W/m^2$

$\mathbf{\beta = 123.75 \ dB}$

7 0

2 years ago

Acceleration is defined as the rate of change for which of the following

Minchanka [31]

_Award brainliest if helped!
Velocity

Note : Not speed as Acceleration is a vector!

6 0

2 years ago

Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m

netineya [11]

Answer: $m \frac{d}{dt}v_{(t)}$

Explanation:

In the image attached with this answer are shown the given options from which only one is correct.

The correct expression is:

$m \frac{d}{dt}v_{(t)}$

Because, if we derive velocity $v_{t}$ with respect to time $t$ we will have acceleration $a$ , hence:

$m \frac{d}{dt}v_{(t)}=m.a$

Where $m$ is the mass with units of kilograms ( $kg$ ) and $a$ with units of meter per square seconds $\frac{m}{s}^{2}$ , having as a result $kg\frac{m}{s}^{2}$

The other expressions are incorrect, let’s prove it:

$\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)}$ This result has units of $kg\frac{m}{s}$

$m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m$ This result has units of $kg$

$m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C$ This result has units of $kgm^{2}$ and $C$ is a constant

$m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m$ This result has units of $kg$

$m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m$ This result has units of $kg$

$\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C$ This result has units of $kg \frac{m^{3}}{s^{3}}$ and $C$ is a constant