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Complete question:
if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.
Answer:
The mutual force between the two point charges is 319.64 N
Explanation:
Given;
distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m
value of the charges, q₁ and q₂ = 2 μC and - μ4 C
Apply Coulomb's law;

where;
F is the force of attraction between the two charges
|q₁| and |q₂| are the magnitude of the two charges
r is the distance between the two charges
k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

Therefore, the mutual force between the two point charges is 319.64 N
<span>reflection, rotation, translation</span>
Answer:
Velocity of the car at the bottom of the slope: approximately
.
It would take approximately
for the car to travel from the top of the slope to the bottom.
Explanation:
The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.
- Let
denote the final velocity of the car. - Let
denote the initial velocity of the car. - Let
denote the acceleration of the car. - Let
denote the distance that this car travelled.
.
Given:
Rearrange the equation
and solve for
:
.
Calculate the time required for reaching this speed from
at
:
.