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Kobotan [32]
2 years ago
8

The most massive stars will eventually collapse entirely giving us what unique structure?

Physics
2 answers:
slega [8]2 years ago
8 0

Answer:

a black hole

Explanation:

yi remeber doin this

hope this helps

mark me brailiest plzz

ra1l [238]2 years ago
6 0
When the cores collapse to form dense stellar objects called neutron stars, they blast off the outer layers of the star in a supernova. In higher-mass red supergiants, however, carbon doesn't burn convectively; this limits neutrino losses and leads to a more extended core with dense material around it.

While the core collapses, the outer layers of material in the star to expand outward. The star expands to larger than it has ever been – a few hundred times bigger! At this point the star is called a red giant. What happens next depends on how the mass of the star.
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Joanne drives her car at a speed of 20 m/s. when she applied her breaks, a frictional force of 2000 N brought her car to a compl
Papessa [141]

Answer:

A) 1000 kg

Explanation:

vf = vi + at

0 = 20 + (a)(10)

a = -2.0 m/s^2

F = ma

2000 = (m)(2)

m = 1000 kg

8 0
1 year ago
2) In coming to a stop, a car leaves skid marks on a road that are 40 m long.
Effectus [21]
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5 0
3 years ago
if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

4 0
3 years ago
Identify the three types of isometric transformations. A. reflection, rotation, translation B. reflection, rotation, dilation C.
inessss [21]
<span>reflection, rotation, translation</span>
4 0
3 years ago
A roller coaster car is traveling at a constant 3 m/s when it reaches a downward slope. On the slope, the car accelerates at a c
kirill [66]

Answer:

Velocity of the car at the bottom of the slope: approximately 20.3\; \rm m \cdot s^{-2}.

It would take approximately 3.9\; \rm s for the car to travel from the top of the slope to the bottom.

Explanation:

The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.

  • Let v denote the final velocity of the car.
  • Let u denote the initial velocity of the car.
  • Let a denote the acceleration of the car.
  • Let x denote the distance that this car travelled.

v^2 - u^2 = 2\, a\cdot x.

Given:

  • u = 3\; \rm m \cdot s^{-1}.
  • a = 4.5\; \rm m \cdot s^{-2}.
  • x = 45\; \rm m.

Rearrange the equation v^2 - u^2 = 2\, a\cdot x and solve for v:

\begin{aligned}v &= \sqrt{2\, a \cdot x + u^2} \\ &= \sqrt{2 \times 4.5\; \rm m \cdot s^{-2} \times 45\; \rm m + \left(3\; \rm m \cdot s^{-1}\right)^{2}} \\ &\approx 20.3\; \rm m \cdot s^{-1}\end{aligned}.

Calculate the time required for reaching this speed from u = 3\; \rm m \cdot s^{-1} at a = 4.5\; \rm m \cdot s^{-2}:

\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{20.3\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1}}{4.5\; \rm m \cdot s^{-2}} \approx 3.9\; \rm m \cdot s^{-1}\end{aligned}.

3 0
3 years ago
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