A rock is thrown downward from an unknown height above the ground with an initial speed of 6.1 m/s. It strikes the ground 1.7 s later. Determine the initial height of the rock above the ground. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m
1 answer:
Answer:
24.531 m
Explanation:
t = Time taken = 1.7 s
u = Initial velocity = 6.1 m/s
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s² = a
Equation of motion
The initial height of the rock above the ground is 24.531 m
You might be interested in
Answer:
nun wbu
Explanation:
Answer:
well, as u can tell the top layer will always be the youngest layer aka the newest layer. The farther u go down the older the layers get. So the deeper u dig the farther back in time we see.
Explanation:
Force equals mass times acceleration. Or: F=ma Plug it in: 5=10a 5/10=(10a)/10 .5m/s²=a
Answer: Gravitational force between the two masses does not depend on the medium separating two masses.
Answer:
anaemia, low blood pressure etc.