Question

A wire is 1.1 m long and 0.91 mm in cross-sectional area. It carries a current of 4.4 A when a 1.8 V potential difference is applied between its ends. Calculate the conductivity of the material of which this wire is made. Number Units The number of significant digits is set to 2; the tolerance is +/-2%

Answer 1

Answer:

The conductivity of the material from which the conductor is made is 2.95 x10⁶  [S. m⁻¹]  .

Explanation:

L= 1.1m

S= 0.91 mm²= 9.1 x10⁻⁷ m²

I= 4.4 A

V= 1.8V

$\frac{V}{I} =R\\\\\frac{1.8V}{4.4A} =R= 9/22 ohms$

R=9/22Ω

$R=\frac{L}{σ . S} \\\\Conductivity=sigma=\frac{L}{R.S} \\\\Conductivity= \frac{1.1m}{9/22 ohms . 9.1 E10 (-7) square meters}$

Conductivity=2.95 x10⁶  [S. m⁻¹]