Answer:
For vector u, x component = 10.558 and y component =12.808
unit vector = 0.636 i+ 0.7716 j
For vector v, x component = 23.6316 and y component = -6.464
unit vector = 0.9645 i-0.2638 j
Explanation:
Let the vector u has magnitude 16.6
u makes an angle of 50.5° from x axis
So ![u_x=ucos\Theta =16.6\times cos50.5=10.558](https://tex.z-dn.net/?f=u_x%3Ducos%5CTheta%20%3D16.6%5Ctimes%20cos50.5%3D10.558)
Vertical component ![u_y=usin\Theta =16.6\times sin50.5=12.808](https://tex.z-dn.net/?f=u_y%3Dusin%5CTheta%20%3D16.6%5Ctimes%20sin50.5%3D12.808)
So vector u will be u = 10.558 i+12.808 j
Unit vector ![u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j](https://tex.z-dn.net/?f=u%3D%5Cfrac%7B10.558i%2B12.808j%7D%7B%5Csqrt%7B10.558%5E2%2B12.808%5E2%7D%7D%3D0.636i%2B0.7716j)
Now in second case let vector v has a magnitude of 24.5
Making an angle with -15.3° from x axis
So horizontal component ![v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316](https://tex.z-dn.net/?f=v_x%3Dvcos%5CTheta%20%3D24.5%5Ctimes%20cos%28-15.3%29%3D23.6316)
Vertical component ![v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464](https://tex.z-dn.net/?f=v_y%3Dvsin%5CTheta%20%3D24.5%5Ctimes%20sin%28-15.3%29%3D-6.464)
So vector v will be 23.6316 i - 6.464 j
Unit vector of v ![=\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j](https://tex.z-dn.net/?f=%3D%5Cfrac%7B23.6316i-6.464%7D%7B%5Csqrt%7B23.6316%5E2%2B6.464%5E2%7D%7D%3D0.9645i-0.2638j)
Answer:
Your answer should be Cooled Air
Explanation:
Answer:
Earth is nearest the Sun in July and farthest away in July.
Explanation:
Answer:
90 meters
Explanation:
Given:
x₀ = 0 m
v₀ = 0 m/s
v = 30 m/s
t = 6 s
Find:
x
x = x₀ + ½ (v + v₀)t
x = 0 + ½ (30 + 0)(6)
x = 90
The car travels 90 meters.