Molar mass Cu(OH)₂ = 97.561 g/mol
97.561 g Cu(OH)₂ --------------- 6.02x10²³ atoms
? g Cu(OH)₂ -------------------- 9.1x10²⁵ atoms
mass = 9.1x10²⁵ * 97.561 / 6.02x10²³
mass = 8.87x10²⁷ / 6.02x10²³
mass = 14734.2 g
hope this helps!
Answer:
<h2>377 kPa</h2>
Explanation:
The original pressure can be found by using the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we're finding the original pressure
![P_1 = \frac{P_2V_2}{V_1} \\](https://tex.z-dn.net/?f=P_1%20%3D%20%20%5Cfrac%7BP_2V_2%7D%7BV_1%7D%20%20%5C%5C)
150 kPa = 150,000 Pa
We have
![P_1 = \frac{150000 \times 166}{66} = \frac{24900000}{66} \\ = 377272.72...](https://tex.z-dn.net/?f=P_1%20%3D%20%20%5Cfrac%7B150000%20%5Ctimes%20166%7D%7B66%7D%20%20%3D%20%20%5Cfrac%7B24900000%7D%7B66%7D%20%20%5C%5C%20%20%3D%20377272.72...)
We have the final answer as
<h3>377 kPa</h3>
Hope this helps you
It changes the rate of growth that cells usually undergo.
Answer:
a) distance is 4+7+1+8=20 blocks
b) displacement is 10 blocks
Explanation:
find displacement: x and y
x axis displacement = 4-1 = 3 blocks
y axis displacement = -7+8= 1 block
displacement = the square root of 3^2 + 1^2
= 9+1 = 10 blocks.
You can find the angle of displacement with respect to the initial position using trig identities, if you wish.
Answer:
Na₂CO₃•H₂O
Explanation:
After it is heated, the remaining mass is the mass of sodium carbonate.
30.2 g Na₂CO₃
Mass is conserved, so the difference is the mass of the water:
35.4 g − 30.2 g = 5.2 g H₂O
Convert masses to moles:
30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃
5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O
Normalize by dividing by the smallest:
0.285 / 0.285 = 1.00 mol Na₂CO₃
0.289 / 0.285 = 1.01 mol H₂O
The ratio is approximately 1:1. So the formula of the hydrate is Na₂CO₃•H₂O.