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Alexxandr [17]
2 years ago
5

Write net ionic equations for gas-forming reactions. Write a net ionic equation for the reaction that occurs when solid barium c

arbonate is combined with excess aqueous hydroiodic acid.
Chemistry
1 answer:
AysviL [449]2 years ago
7 0

Answer: BaCO3(s) + 2H+(aq) --> Ba+2 + H2O(l) + CO2(g)

Explanation: Net ionic equations show only the species or atoms that participate in the reaction, in this case gas-forming

When solid barium carbonate is combined with excess aqueous hydroiodic acid the reaction that take place is.

BaCO3(s) + 2HI(aq) --> BaI2 (aq) + H2O(l) + CO2(g)

To write a ionic equation is necesary to separte the species that are dissociated in water (ag) and expresed it as ions showing the charge

BaCO3(s) + 2I-(aq) + 2H+(aq) --> Ba+2 + 2I- (aq) + H2O(l) + CO2(g)

Since I- is present in both sides of the reaction, it's eliminated in the net ionic equation, and the final expression is:

BaCO3(s) + 2H+(aq) --> Ba+2 + H2O(l) + CO2(g)

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Answer:

\boxed{3}

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\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

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<h3><u>Answer;</u></h3>

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