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2 years ago

C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP is the chemical equation for

Chemistry

1 answer:

Jobisdone [24]2 years ago

3 0

Answer:

C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP is the chemical equation for cellular respiration

Explanation:

Cellular respiration is the process by which cells breakdown glucose molecules to produce energy in the form of ATP molecules and release waste products such as carbon dioxide and water molecules. Cellular respiration involves a series of reaction pathways such as glycolysis, pyruvate oxidation, citric acid cycle and the oxidative phosphorylation pathway.

The first step of glycolysis breaks down a glucose molecule to release two pyruvate molecules.

In pyruvate oxidation, two molecules of pyruvate are oxidized to acetyl-CoA molecules.

In the citric acid cycle, the acetyl-CoA molecules are used to produce the electron carriers NADH and FADH2.

In the oxidative phosphorylation pathway, NADH and FADH2 donate their electrons to oxygen and ATP molecules are produced using the energy of electron transfer and proton-pumping.

The overall equation for cellular respiration is given as:

C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP

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Construct a three-step synthesis of 3-bromo-3-methyl-2-butanol from 2-methyl-2-butene by dragging the appropriate formulas into

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Answer:

See explanation

Explanation:

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4 0

2 years ago

At 350 k, kc = 0.142 for the reaction 2 brcl(g) ⇀↽ br2(g) + cl2(g) an equilibrium mixture at this temperature contains equal con

djyliett [7]

0.114 mol/l
The equilibrium equation will be:
Kc = ([Br2][Cl2])/[BrCl]^2
The square factor for BrCl is due to the 2 coefficient on that side of the equation.
Now solve for BrCl, substitute the known values and calculate.
Kc = ([Br2][Cl2])/[BrCl]^2
[BrCl]^2 * Kc = ([Br2][Cl2])
[BrCl]^2 = ([Br2][Cl2])/Kc
[BrCl] = sqrt(([Br2][Cl2])/Kc)
[BrCl] = sqrt(0.043 mol/l * 0.043 mol/l / 0.142)
[BrCl] = sqrt(0.001849 mol^2/l^2 / 0.142)
[BrCl] = sqrt(0.013021127 mol^2/l^2)
[BrCl] = 0.114110152 mol/l
Rounding to 3 significant figures gives 0.114 mol/l

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3 years ago

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2 years ago

Read 2 more answers

7.66 Write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water,

White raven [17]

Explanation:

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$K_2O(s)+H_2O(l)\rightarrow 2KOH(aq)$

According to reaction,1 mole of potassium oxide reacts with 1 mole of water to give 1 mole of potassium hydroxide.

(b) diphosphorus trioxide with water

$P_2O_3(s)+3H_2O(l)\rightarrow 2H_3PO_3(aq)$

According to reaction,1 mole of diphosphorus trioxide reacts with 2 moles of water to give 2 moles of phosphorus acid.

(c) chromium(III) oxide with dilute hydrochloric acid,

$Cr_2O_3(s)+6HCl(aq)\rightarrow 2CrCl_3(aq)+3H_2O(l)$

According to reaction,1 mole of chromium(III) oxide reacts with 6 moles of hydrochloric acid to give 2 moles of chromium(III) chloride and 3 moles of water.

(d) selenium dioxide with aqueous potassium hydroxide

$SeO_2 (s)+2KOH (aq)\rightarrow K_2SeO_3(aq)+H_2O(l)$

According to reaction,1 mole of selenium dioxide reacts with 2 moles of potassium hydroxide to give 1 mole of potassium selenite and 1 mole of water.

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3 years ago