Answer:
Equation of circle in standard form with centre (0, – 10) and radius 6. 
Step-by-step explanation:
We need to write equation of circle in standard form with centre (0, – 10) and radius 6.
The equation of circle is: 
where (h,k) is centre of circle and r is radius
We are given centre (0,-10) so, h=0, k=-10 and radius r = 6
Putting values and finding equation:
So, equation of circle in standard form with centre (0, – 10) and radius 6.
Answer:
3 hours
Step-by-step explanation:
15 workers * 7 hours = 105 worker hours
105 worker hours / 35 workers = 3 hours
We have that
<span>y=1/2x-3
1) the slope of this line equation is m=(1/2)
2) the coordinates of the y intercept are
for x=0
y=-3
point (0,-3)
3)</span>the coordinates of the x intercept are
for y=0
0=(1/2)x-3------> (1/2)x=3----> x=6
point (6,0)
<span>if the line is dilated by a factor of 3
then
</span>y=1/2x-3--------> 3y=3*[1/2x-3]-----> 3y=(3/2)x-9
3y=(3x-18)/2-------> y=(3x-18)/6--------> y=(3/6)x-18/6
y=(3/6)x-18/6
so
1) the slope of this line equation is m=(3/6)-----> 3/6=1/2
2) the coordinates of the y intercept are
for x=0
y=-18/6-------> y=-3
point (0,-3)
3)the coordinates of the x intercept are
for y=0
0=(3/6)x-18/6------> (3/6)x=18/6----> x=18/3------> x=6
point (6,0)
therefore
the equation of the line
y=1/2x-3 is the same that the equation of the line y=(3/6)x-18/6
<span>the equation does not change because the slope and the x and y intercepts do not change either</span>
Answer:
5/1
Step-by-step explanation:
