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3 years ago

Lisa is 9 years younger than her brother Paul. Seven years ago Paul was 4 times as old as Lisa. How old is Paul now?

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

Answer:

Look at step-by-step

Step-by-step explanation:

the key word "times" tells us we are multiplying something

Lisa is 9 years younger than her brother

Paul is 4 <u><em>times</em></u> the age of Lisa seven years ago

so now that we have some of this info lets just try to figure this out yeah XD

so we know that she is 9 years younger than her brother right

so lets just say he's 19 and she's 10

10 - 7 = 3

19 - 7 = 12

seven years ago then she was 3 and her brother was 12

SOOOOO

when you divide 12 by 3 you get 4 (4 times older)

when you multiply 3 by 4 you get twelve.

thats where the 4 comes into play

amd technically this question is weird as heck because it doesnt give you numbers to start out with (ages i mean) and so you just woould have to make up some random age.

Hopefully i am not completely wrong :)

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3 years ago

If α, β are the zeroes of the polynomials f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) =

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Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

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2 years ago

If g(x) = 3x^2+2x-1. Find g(-1).

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g(x) = 3x² + 2x - 1

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= 3(1) -2 -1

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3 years ago