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miskamm [114]
3 years ago
9

What will happen if a crystal of ammonium nitrate is added to a supersaturated ammonium nitrate solution? Will it dissolve in wa

ter

Chemistry
1 answer:
romanna [79]3 years ago
5 0

Answer:

It will not dissolve. More crystals will separate from the solution.  

Step-by-step explanation:

If you add a crystal of ammonium nitrate to a supersaturated solution of the solute, it will not dissolve.  

Instead, it will act as a "seed" on which more ammonium nitrate crystals will form.

They will separate from the solution as long, colourless, needle-like crystals until the solution is no longer supersaturated.

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C(graphite) + O2(g) → CO2(g) + 94.05 kcal C(diamond) + O2(g) → CO2(g) + 94.50 kcal What could you infer from the information giv
olga nikolaevna [1]
Looking at both reactions, we can see that the combustion of carbon, graphite or diamond, leads to the formation of carbon dioxide and energy. Since energy is a product of the reaction, we known that this is an exothermic reaction. The value of the change in enthalpy, ΔH, will be negative.

A negative value of ΔH in each exothermic reaction suggests that the carbon dioxide product is at a lower energy than the reactants. And since more energy is released in the combustion of diamond compared to graphite, we know that diamond has a higher internal energy than graphite.
7 0
3 years ago
Read 2 more answers
Given 2.91 moles of a gas in a 500 milliliter-container, if the temperature is found to be 31 degrees Celsius, what is the press
kari74 [83]
Use the PV = nRT equation T is in Kelvins = 31 + 273 = 304 K

P(0.5) = (2.91)(0.0821)(304)
P(0.5) = 72.6289
P = 145.25 atm or 1.45x10^2 atm
3 0
3 years ago
Read 2 more answers
Which of the following processes does our Sun and other stars in our galaxy use to create energy?
Usimov [2.4K]

Answer:

fusion reaction

The simple answer is that the sun, like all stars, is able to create energy because it is essentially a massive fusion reaction. Scientists believe that this began when a huge cloud of gas and particles (i.e. a nebula) collapsed under the force of its own gravity – which is known as Nebula Theory.

Explanation:

hope this helps

5 0
2 years ago
What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


4 0
3 years ago
What is the density of an object with a mass of 40.0 g and a volume of 80.0 cm3
Komok [63]
Density = mass/volume
D  = 40/80 = 0.5g
D= 0.5g
8 0
3 years ago
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