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Feliz [49]
3 years ago
12

Please help with question 4A,B please Thank you

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0
<h3>Given</h3>
  • C(t) = 40 cm + t·(2/5 cm/s) . . . circumference of a circle vs time
<h3>Find</h3>
  • dr/dt for radius r
  • r at t=4 seconds
<h3>Solution</h3>

The circumference and radius of a circle are related by

... C = 2πr

so the radius in terms of circumference is

... r = C/(2π)

... r(t) = (40 +0.4t)/(2π) = (1/π)(20 cm + 0.2t cm/s)

Then dr/dt is

... dr/dt = 0.2/π cm/s

And the radius at t=4 s is

... r(4) = (1/π)(20 + 0.2·4) cm

... r(4) = 20.8/π cm

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Find the length of side x in simplest radical form with rational denominator. the short leg is root 2 and the long leg is x we d
kirill115 [55]

Answer:

√2 + x

Step-by-step explanation:

To obtain the hypotenus, h:

Using Pythagoras rule :

h² = opposite² + Adjacent²

Opposite = √2

Adjacent= x

h² = (√2)² + x²

Take the square root of both sides

h = √2 + x

Hence, the hypotenus is √2 + x

5 0
3 years ago
(3 − 4i)(5 + 2i)<br><br> A. 15 − 8i<br> B. 23 − 14i<br> C. 15 − 8i2<br> D. 15 − 14i − 8i2
choli [55]

Answer:

B.23-14i

Step-by-step explanation:

(3x5)+(3x2i)-(4ix5)-(4ix2i)

15+6i-20i-8(-1)

15+6i-20i+8

23-14iฟ

8 0
3 years ago
In 1/8 days, a construction crew built 1/4 miles of a road. What is the unit rate in miles per day.
tigry1 [53]

The unit rate of road construction is 2 miles per day.

Step-by-step explanation:

Given,

In \frac{1}{8} days \frac{1}{4} miles road is constructed.

To find

The rate of road constructed per day

Method

We will apply unitary method to solve it.

Now,

In \frac{1}{8} days \frac{1}{4} miles road is constructed.

In 1 day the road will be constructed = \frac{1}{4} ÷ \frac{1}{8} miles

= 2 miles

4 0
3 years ago
Write a quadratic function in standard form with zeros 1 and -10
Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

The factored form of a quadratic equation is:

f(x)=a(x-\alpha)(x-\beta)

Where \alpha and \beta are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

f(x)=a(x-1)(x-(-10))

f(x)=a(x-1)(x+10)

Operating:

f(x)=a(x^2+10x-x-10)

Joining like terms:

f(x)=a(x^2+9x-10)

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

\boxed{f(x)=x^2+9x-10}

6 0
3 years ago
Graph the function f(x) = 3x2 - 6x - 4. Make sure you plot at least 3 points on the graph and then list at least 3 points in you
Sloan [31]

Answer:

(0,2)(1,-4)((-1,8)

Step-by-step explanation:


3 0
3 years ago
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