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igor_vitrenko [27]
3 years ago
11

Question 5 (2 points)

Physics
2 answers:
Elis [28]3 years ago
6 0

If you WANT to increase the distance traveled over the same period of time, then you HAVE TO increase the speed.

This happens millions of times every day, when mothers all over the world yell "HURRY UP !" to their kids.

MrRa [10]3 years ago
4 0
A, increase the speed. Going more distance in a same period of time would mean you have to be quicker in order to reach that distance in the same time.
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You design toys for a toy company. Your boss wants you to hook up the lights in the toy car you are working on in the cheapest w
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put the car on fire

Explanation:

if you put it on fire you would have a lot of light now

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Clouds dump around 100 billion gallons of water on rainforests each year. How much rain is evaporated from the rivers, lakes and
posledela
The correct answer is this one: "D) significantly more than 100 billion gallons ." Clouds dump around 100 billion gallons of water on rainforests each year. The amount of  rain is evaporated from the rivers, lakes and surface of rainforests each year is significantly more than 100 billion gallons<span> </span>
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A car is going south on I-69 at 33 m/s (74 mph). The car has good brakes so its maximum braking acceleration is – 8.5 m/s^2 . Tr
dmitriy555 [2]

Answer:

1.69515 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-33^2}{2\times -8.5}\\\Rightarrow s=64.06\ m

The distance between the traffic and the car after braking is 120-64.06 = 55.94 m

Time = Distance / Speed

\text{Time}=\frac{55.94}{33}\\\Rightarrow \text{Time}=1.69515\ seconds

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What are the differences and the similarities between psychology and the social science
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Answer:

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A youngster having a mass of 50.0 kg steps off a 1.00 m high platform. If she keeps her legs fairly rigid and comes to rest in 1
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The average act on her during the deceleration is 4.47 meters per second.                                                                

<u>Explanation</u>:

<u>Given</u>:

youngster mass m = 50.0 kg

She steps off a 1.00 m high platform that is s = 1 meter

She comes to rest in the 10-meter second

<u>To Find</u>:

The average force and momentum

<u>Formulas</u>:

p = m * v

F * Δ t = Δ p

vf^2= vi^2+2as

<u>Solution</u>:

a = 9.8 m/s

vi = 0

vf^2= 0+2(9.8)(1)

vf^2 = 19.6

vf = 4.47 m/s .

Therefore the average force is 4.47 m/s.                                          

                                 

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