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3 years ago

What do you think we can learn about Earth's history by looking at the Grand Canyon?

1 answer:

5 0

We can look at all the ages of the earth since it’s a big crack is reveals many layers of the earth and we can know about chemicals and metals that were in earth and diffrent times

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R = (2+2+1) i - (t+1)] + t3 k<br> what is the direction of initial velocity

Wittaler [7]

Answer:

In the - j direction, that is negative of the y-axis

Explanation:

As typed in the question, the position of the object is given by the expression in three component ( i, j, k) form:

r (t) = 5 i - (t + 1 ) j + t^3 k

and since the velocity is the derivative of position with respect to time, by doing the derivative of this expression we get:

v(t) = 0 i - 1 j +3 t^2 k

which for the initial velocity requested (that is at time zero) we have:

v(t) = 0 i - 1 j +3 (0)^2 k = = 1 j

Then the direction of the initial velocity is entirely in the direction of the j versor, that is pointing to the negative of the y-axis.

4 0

3 years ago

A 3.53-g sample of aluminum completely reacts with oxygen to form 6.67 g of aluminum oxide. find percent composition

katrin2010 [14]

The mass percent composition of aluminum is 52.9% in aluminum oxide.

Mass of the aluminum = 3.53 g

Mass of the aluminum oxide = 6.67 g.

The mass percent of a substance is the mass of the substance divided by the mass of the compound into 100.

Aluminum reacts with oxygen to form aluminum oxide.

The overall balanced equation for the reaction is,

$Aluminum + Oxygen→Aluminum \: oxygen$

$4Al +3O _{2}→2Al _{2}O _{3}$

The mass percent composition of aluminum in the aluminum oxide is,

$Mass \: percent = \frac{ Mass \: of \: the \: substance}{ Mass \: of \: the \: compound} \times 100$

$Mass \: percent = \frac{Mass \: of \: the \: aluminum}{ Mass \: of \: the \: aluminum \: oxide } \times 100$

$Mass \: percent = \frac{3.53}{6.67 } \times 100$

= 52.9 %

Therefore, the mass percent composition of aluminum is 52.9% in aluminum oxide.

To know more about aluminum oxide, refer to the below link:

brainly.com/question/25869623

#SPJ4

7 0

1 year ago

A 2.0-mm-long, 1.0-mmmm-diameter wire has a variable resistivity given by rho(x)=(2.5×10−6)[1+(x1.0m)2]Ωmrho(x)=(2.5×10−6)[1+(x1

Tresset [83]

Answer:

1.144 A

Explanation:

given that;

the length of the wire = 2.0 mm

the diameter of the wire = 1.0 mm

the variable resistivity R = $\rho (x) =(2.5*10^{-6})[1+(\frac{x}{1.0 \ m})^2]$

Voltage of the battery = 17.0 v

Now; the resistivity of the variable (dR) can be expressed as = $\frac{\rho dx}{A}$

$dR = \frac{(2.5*10^{-6})[1+(\frac{x}{1.0})^2]}{\frac{\pi}{4}(10^{-3})^2}$

Taking the integral of both sides;we have:

$\int\limits^R_0 dR = \int\limits^2_0 3.185 \ [1+x^2] \ dx$

$R = 3.185 [x + \frac {x^3}{3}}]^2__0$

$R = 3.185 [2 + \frac {2^3}{3}}]$

R = 14.863 Ω

Since V = IR

$I = \frac{V}{R}$

$I = \frac{17}{14.863}$

I = 1.144 A

∴ the current if this wire if it is connected to the terminals of a 17.0V battery = 1.144 A

8 0

3 years ago

Which car has the most kinetic energy?

Andru [333]

50kg driving at 30kph because it’s the heaviest yet fastest!

8 0

3 years ago

Juno created a diagram to describe characteristics of freezing and deposition. Which labels belong in the areas marked X and Y?

DIA [1.3K]

the correct answer to this question is A

7 0

3 years ago

Read 2 more answers