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andrew11 [14]
3 years ago
12

What is density?

Physics
2 answers:
a_sh-v [17]3 years ago
8 0

Answer:

B- The amount of matter in a certain

amount of space

Explanation:

Density is the amount of matter an object has in a certain space. To find density, divide the mass of an object by the volume of an object.

WINSTONCH [101]3 years ago
3 0

Answer:

C- How much water it displaces

Explanation:

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A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What h
MariettaO [177]

Answer:

161.86 N

Explanation:

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g here is acceleration due to gravity =9.81 m/sec^2

coefficient of friction between the box and the surface μ= 0.3

the friction force F_s= μmg= 0.3×55×9.81

=161.86 N

to move the ball horizontal force required is 161.86 N

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Electricity from the local power company costs 7.22 cents/kWh. A homeowner wishes to pay a maximum of 25 cents per month for the
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3 years ago
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You run a race with your friend. At first you each have the same kinetic energy, but then you find that she is beating you. When
Blizzard [7]

Answer:

52.49 Kg

Explanation:

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3 0
3 years ago
The core of a star must be at temperature of _____ degrees Celsius for hydrogen fusion to take place. 10,000 100,000 1,000,000 1
disa [49]
The core of a star must be at the temperature of 10,000,000 degrees Celsius for hydrogen fusion to begin. 
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3 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
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