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3 years ago

What may thermal energy stores also be called? PLEASE REALLY NEED THE HELP!

Physics

1 answer:

ollegr [7]3 years ago

3 0

Answer:

The thermal energy is the sum of the potential energy and kinetic energy that is known to make all the particle in an object it is the energy that is responsible for its temperature heat is the flow of thermal energy thermal energy is the result of something that has some internal temperature which can be measured

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Homeostasis can require the control of many different variables in organisms. Homeostasis regarding internal body temperature is

12345 [234]

Answer:

idk because idk

Explanation:

idk

4 0

3 years ago

Using the right amount of significant figures, calculate the answer to the following problem, 15.33879 + 15.555

MAXImum [283]

Answer:

there are 7 significant figures

Explanation:

15.33879+15.555

=30.89379

there are 7 significant figures

mark me as brainliest plyyzzz

7 0

3 years ago

HELP ASAP

Sladkaya [172]

Answer:
I think the answer is
C) iron nails are attracted towards all materials

8 0

2 years ago

A 0.0450 kg bullet is accelerated from rest to a speed of 425 m/s in a 2.25 kg rifle (which is inititally at rest). The pain of

Mrac [35]

Answer:

If the rifle is held loosely away from the shoulder, the recoil velocity will be of -8.5 m/s, and the kinetic energy the rifle gains will be 81.28 J.

Explanation:

By momentum conservation, and given the bullit and the recoil are in a straight line, the momentum analysis will be unidimentional. As the initial momentum is equal to zero (the masses are at rest), we have that the final momentum equals zero, so

$0=P_{f}=m_{b} *v_{b}+m_{r}*v_{r}$

now we clear $v_{r}$ and use the given data to get that

$v_{r}=-8.5\frac{m}{s}$

But we have to keep in mind that the bullit accelerate from rest to a speed of 425 m/s, then if the rifle were against the shoulder, the recoil velocity would be a fraction of the result obtained, but, as the gun is a few centimeters away from the shoulder, it is assumed that the bullit get to its final velocity, so the kick of the gun, gets to its final velocity $\bold{v_{r}}$ too.

Finally, using $v_{r}$ we calculate the kinetic energy as

$K=\frac{1}{2}m_{r}v_{r}^{2}=81.28J$

3 0

3 years ago

A B-52 bomber jet flies at a horizontal velocity of 286.2 m/s and at an altitude of 7500 m above the ground.

kykrilka [37]

Answer:

you need to divide 7500/286.2

3 0

2 years ago