Graph g(x) = f(x + 2)

Joe is performing a dilation. One of his points is Y'(-4, 2), and another point is Y(-2, 1). What scale factor is he using?

IRINA_888 [86]

I would say c.-1/2 but I'm not certain

5 0

4 years ago

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What does a linear function look like

Y_Kistochka [10]

Y= f(x) = a+bx
example: f(x) = 3x+2

6 0

3 years ago

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I'm completely lost?

aliya0001 [1]

13000-5600=7400...that's about it, just multiply then subtract

4 0

3 years ago

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George would like to build a garden this year, George measure out his proposed garden and would like to know how many square fee

Blababa [14]

Answer:

The area is 105.5ft^2

Step-by-step explanation:

Required

The area of the composite figure

The figure can be divided to 2 shapes

(1) Rectangle: Length = 6ft and Width = 8ft

(2) Trapezoid: Height = 5ft (i.e. 8 - 3), Parallel sides = 9ft and 14ft (i.e. 20 - 6)

The area of the rectangle is:

$Area = 6 * 8 = 48$

The area of the trapezoid is:

$Area = \frac{1}{2}(9 + 14) * 5$

$Area = \frac{1}{2}(23) * 5$

$Area = 11.5 * 5$

$Area = 57.5$

So, the area of the garden is:

$Total = 48 + 57.5$

$Total = 105.5$

5 0

3 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

3 years ago

Graph g(x) = f(x + 2) - 5.