The concentration of a solution can be expressed in
2 answers:
The concentration of a solution can be expressed in <u>(4) moles per liter</u>
<h3>Further explanation </h3>Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.
In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
- Kelvin
Temperature is used as a guide to the level of heat energy from objects
Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin
- milliliters
Volume is a derivative quantity derived from the length
The unit of volume can be expressed in liters or milliliters or cubic meters
- joules per kilogram
Energy can be interpreted as the ability to do work
Energy units can be stated in joules or calories (J or Cal)
- moles per liter
Mole
The mole itself is the number of particles contained in a substance amounting to 6.02.10²³
Mole is the result of dividing the amount of substance mass and its molar mass
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
<h3>n = V x M </h3><h3>Learn more </h3>
the concentrations for the two ions
The molarity of the stock solution of luminol
volume of 0.100 M Na₃PO₄
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We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).
Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).
To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
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