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3 years ago

Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.

Chemistry

1 answer:

N76 [4]3 years ago

6 0

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

=22.4dm

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

)

⇒1000=−1×2.303×2×273×log(

22.4

)

Explanation:

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Identify the examples of diffusion in the list below. Check all that apply.

Fynjy0 [20]

Answer;

A teacher takes the cap off a permanent marker. A few minutes later, students at the back of the classroom complain about the odor of the marker.
A cooking school student burns a piece of toast. Soon, the entire kitchen smells like burnt toast.
Toxic fumes produced by a chemical factory are detected in the air in a town several miles away.

<h3>Explanation;</h3>

Diffusion is a type of passive transport that involves the movement of particles from a region of high concentration to a region of low concentration.
Diffusion takes place in liquids and gases, since their particles can move randomly from one region to another.
Therefore, diffusion results from the random movement of particles in which the net movement is down the concentration gradient that is, from a region of high concentration to a region of low concentration.

4 0

4 years ago

Read 2 more answers

How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

Pie

Answer: The mass of sodium acetate that must be added is 30.23 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of acetic acid solution = 0.200 M

Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

$[CH_3COONa]=?mol$

$[CH_3COOH]=0.200mol$

pH = 5.00

Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

7 0

3 years ago

How do you balance a chemical equation?

Marianna [84]

Answer:

When you balance a chemical equation you change coefficients.You never change subscripts. A coefficient is a whole number multiplier. To balance a chemical equation you add the coefficients to make sure there are the same number of atoms on each side of the arrow.

Explanation:

Hope this helps. MARK BRAINLEST!!

7 0

4 years ago

While eating dinner with her family, Tina's mother starts to cough. When Tina

EleoNora [17]

The correct answer is: C. “Tina’s mother has severe FBAO. Tina should begin administering back blows followed by abdominal thrusts if the problem persists.”

Explanation: I did my study and took the test, this was right. :)

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3 years ago

How do compaction and cementation cause sediments and form sedimentary rock

xz_007 [3.2K]

Answer:

Dissolved minerals in the ground water precipitate (crystallize) from water in the pore spaces forming mineral crusts on the sedimentary grains, gradually cementing the sediments, thus forming a rock

Explanation:

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3 years ago