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Anon25 [30]
4 years ago
15

I REALLY NEED HELP PLEASE

Physics
1 answer:
iogann1982 [59]4 years ago
6 0
The correct answer is C
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John(body mass=160pounds) is taking off for a long jump. The average ground reaction force Fg at takeoff is 1400 N pointing forw
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Answer:

The free body diagram of John is shown in the attached figure (in the FBD john's mass is supposed to be concentrated at his center of mass and FBD is made of center of mass)

b) As shown in the FBD the ground reaction forces are:

i) In X direction F_{x}=1400cos(35^{o})=1146.81N

ii) In Y direction F_{y}=1400sin(35^{o})=803.0N

c) The respective accelerations in x and y direction's is calculated by newton's second law as indicated under

\sum F_{x}=ma_{x}\\\\\therefore a_{x}=\frac{\sum F_{x}}{m}=\frac{1146.8N}{72.57kg}=15.80m/s^{2}\\\\\sum F_{y}=ma_{y}\\\\\therefore a_{y}=\frac{\sum F_{y}}{m}=\frac{803.00-72.57\times 9.81}{72.57}=1.255m/s^{2}

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The height of a transverse waves is known as its?
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amplitude

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As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
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Answer:

F = 2.6 x 10⁻²² N

Explanation:

According to the Coulomb's Law, the force of attraction or repulsion between two charges is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them. The formula for the force is given as follows:

F = k q₁ q₂/r²

where,

F = Force of Attraction or Repulsion = ?

q₁ = magnitude of first charge = charge on electron = 1.6 x 10⁻¹⁹ C

q₂ = magnitude of second charge = charge on proton = 1.6 x 10⁻¹⁹ C

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r = distance between the charges = 885 nm = 8.85 x 10⁻⁷ m

Therefore,

F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(8.85 x 10⁻⁷ m)²

<u>F = 2.6 x 10⁻²² N</u>

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4 years ago
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