Get To Safety And Call A Fire Department,
Be Alert Of The Signals Of The Presence Carbon Monoxide
Get Routine Checks Of Security Tools
the object distance of both lenses are positive.
Answer:
<h3>473.8 m/s; 473.8 m/s</h3>
Explanation:
Given the initial velocity U = 670m/s
Horizontal velocity Ux = Ucos theta
Vertical component of the cannon velocity Uy = Usin theta
Given
U = 670m/s
theta = 45°
horizontal component of the cannonball’s velocity = 670 cos 45
horizontal component of the cannonball’s velocity = 670(0.7071)
horizontal component of the cannonball’s velocity = 473.757m/s
Vertical component of the cannonball’s velocity = 670 sin 45
Vertical component of the cannonball’s velocity = 670 (0.7071)
Vertical component of the cannonball’s velocity = 473.757m/s
Hence pair of answer is 473.8 m/s; 473.8 m/s
<u>Answer:</u>
0.24 m
<u>Explanation:</u>
Given:
Wave velocity ( v ) = 360 m / sec
Frequency ( f ) = 1500 Hz
We have to calculate wavelength ( λ ):
We know:
v = λ / t [ f = 1 / t ]
v = λ f
= > λ = v / f
Putting values here we get:
= > λ = 360 / 1500 m
= > λ = 36 / 150 m
= > λ = 0.24 m
Hence, wavelength of sound is 0.24 m.
