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djverab [1.8K]
4 years ago
13

What are the three most influential variables that affect electrical force?

Physics
1 answer:
snow_tiger [21]4 years ago
4 0
I know that the answer is 3 because 1+2 is 3
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A solid sphere of radius R carries a fixed, uniformly distributed charge q. Obtain an expression for the magnitude of the electr
NISA [10]

Answer:

The electric field outside the sphere will be \dfrac{qr}{4\pi\epsilon_{0}R^3}.

Explanation:

Given that,

Radius of solid sphere = R

Charge = q

According to figure,

Suppose r is the distance between the point P and center of sphere.

If \rho be the volume charge density,

Then, the charge will be,

q=\rho\times\dfrac{4}{3}\pi R^3.....(I)

Consider a Gaussian surface of radius r.

We need to calculate the electric field outside the sphere

Using formula of electric field

\oint{\vec{E}\cdot \vec{dA}}=\dfrac{Q}{\epsilon_{0}}

E\times4\pi r^2=\dfrac{\rho\dotc \dfrac{4}{3}\pi r^3}{\epsilon_{0}}

Put the value from equation (I)

E\times4\pi r^2=\dfrac{qr^3}{\epsilon_{0}R^3}

E=\dfrac{qr}{4\pi\epsilon_{0}R^3}

Hence, The electric field outside the sphere will be \dfrac{qr}{4\pi\epsilon_{0}R^3}.

4 0
3 years ago
The measure of an acute angle is between 0 degrees and 180 degrees. true false
lozanna [386]
<span>The measure of an acute angle is between 0 degrees and 90 degrees. It must be smaller than the perpendicular angle i.e., 90 degree. So, the answer of your question would be false.

In short, Your Answer would be "False"

Hope this helps!</span>
4 0
4 years ago
Read 2 more answers
Moving a spring toy up and down will create what kind of wave?
tia_tia [17]
I’m not a 100% sure but I believe the transverse wave
4 0
3 years ago
Read 2 more answers
On the International Space Station an object with mass m = 280 g is attached to a massless string L = 0.97 m. The string can han
katovenus [111]

Answer:

5.16 m/s

Explanation:

The tension in the string provides the centripetal force that keeps the object spinning in circular motion, therefore we can write:

T=m\frac{v^2}{r}

where

T is the tension

m is the mass of the object

v is the speed

r is the radius of the circle

Here we have:

m = 280 g = 0.280 kg

r = L = 0.97 m (the radius of the circle is the length of the string)

The maximum tension allowed is

T = 7.7 N

Therefore, by solving for v, we find the maximum speed allowed before the string breaks:

v=\sqrt{\frac{Tr}{m}}=\sqrt{\frac{(7.7)(0.97)}{.280}}=5.16 m/s

6 0
3 years ago
What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a
astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section areaA = (2.00\times10^{-3})^2\ m

(I). We need to calculate the area of copper wire

Using formula of area

A=\pi r^2

A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2

We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}

R=0.0742\ \Omega

(II). We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}

R=1.75\ \Omega

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

8 0
4 years ago
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