Answer:
3000
Step-by-step explanation:
the 4 next to the 3 means that you will be rounding down.
Answer:
7
Step-by-step explanation:
5 1/4= 5.25
3/4=.75
5.25/0.75=7
Using Pythagorean theorem





Answer:

And on this case we can use the product rule for a derivate given by:

Where
and
And replacing we have this:

Step-by-step explanation:
We assume that the function of interest is:

And on this case we can use the product rule for a derivate given by:

Where
and
And replacing we have this:
