The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration towards the ground. So we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:
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The magnifying power of this telescope is 12,5.
<h3>What is a telescope?</h3>
The telescope is an optical instrument that aims to allow the observation of large objects at long distances, such as galaxies, stars and planets. It consists of two parts: the objective, which can be a lens or a curved mirror, and the eyepiece, made up of a set of lenses.
With that being said and knowing that:
The focal length of the objective of a telescope (fo) = 75cm; The focal length of the eyepiece of a telescope (fe) = 6cm.
Changing the values:
So, The magnifying power of this telescope is 12,5.
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Using the formula:
w = m x g ....... eq1
here w is weight of the object.
m is mass of the object, and
g is the acceleration of gravity.
mass, m = 14 lbm (given)
acceleration of gravity, g= 32.0 ft/
Now, substituting the values in equation (1):
w = 14lbm x 32.0 ft/ = 448 lbm ft/
since, 1 lbf = 32.174 lbm ft/
so, w = 448 x
w = 13.924lbf
Hence, the mass of an object is 13.924 lbf.
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D. Mercury
Its year only takes 88 Earth days.
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Answer:
497.143 nm.
Explanation:
Diffraction grating experiment is actually done by passing light through diffraction glasses, the passage of the light causes some patterns which can be seen on the screen. This is because light is a wave and it can spread.
The solution to the question is through the use of the formula in the equation (1) below;
Sin θ = m × λ. ---------------------------------(1).
Where m takes values from 0, 1, 2, ...(that is the diffraction grating principal maxima).
Also, m × λ = dc/ B -------------------------------------------(2).
We are to find the second wavelength, therefore;
λ2 =( m1/c1) × (c2/m2) × λ1 ------------------------(3).
Where c1 and c2 are the order maximum and m = order numbers. Hence;
λ2 = (1/ .350) × (.870/3) × 600 = 497.143 nm.