Answer:
The maximum range 
m
Explanation:
Given,
The initial velocity of the car, u = 30 m/s
The height of the cliff, h = 50 m
Let the car drives off the cliff with a horizontal velocity of 30 m/s.
The formula for a projectile that is projected from a height h from the ground is given by the relation
m
Where,
g - acceleration due to gravity
Substituting the values in the above equation
= 132.72 m
Hence, the car lands at a distance, m
Answer:
(a). Energy is 64,680 J
(b) velocity is 51.43m/s
(c) velocity in mph is 115.0mph
Explanation:
(a).
The potential energy 
of the payload of mass 
is at a vertical distance 
is
.
Therefore, for the payload of mass 
at a vertical distance of 
, the potential energy is
(b).
When the payload reaches the bottom of the shaft, all of its potential energy is converted into its kinetic energy; therefore,
(c).
The velocity in mph is
"Celestial" = anything to do with the sky
("Cielo" ..... Spanish for "sky"
"Ceiling" ... that thing up over your head
"Caelum" .. Latin for "heaven")
"Terrestrial" = anything to do with the Earth
("Terra" ... Latin for "Earth")
If its not Distance traveled then its energy
Answer:
9ms^2
Explanation:
since ,Force=mass*acceleration
then, acceleration=force/mass
and, Force=90N
Mass=10pound
therefore, acceleration=90/10
=9ms^2
