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Fed [463]
3 years ago
9

A rocket is fired straight up. It contains two stages (Stage 1 and Stage 2) of solid rocket fuel that are designed to burn for 1

0.0 and 5.00 s, respectively, with no time interval between them. In Stage 1, the rocket fuel provides an upward acceleration of 15.0 m/s2. In Stage 2, the acceleration is 10.0 m/s2. Neglecting air resistance, calculate the maximum altitude above the surface of Earth of the payload and the time required for it to return to the surface. Assume the acceleration due to gravity is constant.1) Calculate the maximum altitude.
2) Calculate time required to return to the surface (i.e. the total time of flight).

Physics
1 answer:
insens350 [35]3 years ago
6 0

Answer: a) 1875m. (b) 8.66s

Explanation:

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The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2
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Answer:

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2 in front of water and 1 in front of oxygen

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NOT adding the coefficient 3 in front of H2 and the coefficient 2 in front of NH3

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V2O5 + 5CaS → 5CaO + V2S5

One half of a balanced chemical equation is shown.

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Substances A and B react in a ratio of A + B → AB. Colin was combining substance A and substance B to form substance AB. He added 10 g of substance A and 45 g of substance B.

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Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting equation?

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Which best describes the law of conservation of mass?

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6 0
3 years ago
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Answer:

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7 0
3 years ago
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How many grams of CO-60 result in 1 Millicuire of activity? How many years until the activity decays to 1 microcuire tl/2 =5.3 Y
vredina [299]

Answer:

m =8.81*10^{-6}grams

time t = 52.8 year

Explanation:

GIVEN DATA:

the half life of the CO-60 is, T_1/2 = 5.27 years = 1.663 e+8 s

activity dN/dt = 1 mCi = 3.7 X 10^7 decay/s

activity ,  dN/dt = N* \lambda

              \frac{dN}{dt} = N* \frac{ln2}{T_1/2}

                   N = \frac{(dN/dt )(T1/2)}{ln2}

                      = ( 3.7 X 10^7 )(1.663*10^8 ) / ln2

                      = 8.877*10^{16}

Number of moles:

     n = N/NA = 8.877*10^{16} / 6.022X10^23 = 1.474*10^{-7} mol

mass of the CO-60 is,

   m = n*M = [1.474*10^{-7} mol]*[59.93 grams /mol] = 8.81*10^{-6}grams

-----------------------------------------------------------------------------------------

    time t = -[T1/2 / ln2]*ln[N/N0]

             = - [5.3 years / ln2]*ln[1x10-6/1x10-3]

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8 0
3 years ago
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trapecia [35]

The speed of the toy when it hits the ground is 2.97 m/s.

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P.E = K.E

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Substitute the given values and solve the speed;

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Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

7 0
2 years ago
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