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natita [175]
2 years ago
10

A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20, what is the exact distance that the seismic station is away from

the epicenter?
Physics
1 answer:
maxonik [38]2 years ago
4 0

The exact distance from the seismic station to the epicenter is 6000 km.

<h3>Epicenter of earthquake</h3>

The earthquake's epicenter is the point above the fault location on the earth's surface.

Given that:

A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20.

Difference in arrival time = 3:07:20 - 3:00:00 = 7 minutes 20 seconds

From the earthquake time travel graph, a time difference of 7 min 20 sec is at x = 6

The exact distance from the seismic station to the epicenter is 6000 km.

Find out more on Epicenter of earthquake at: brainly.com/question/1969968

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Calculate the number of millimeters in 2.13 kilometer.
lapo4ka [179]

The answer is 2,130,000

6 0
4 years ago
The electrical resistance of an element in a platinum resistance thermometer at 100°c, 0°c and room temperature are 75.00Ω, 63.0
Dominik [7]

Answer:

16.6 °C

Explanation:

From the question given above, the following data were obtained:

Temperature at upper fixed point (Tᵤ) = 100 °C

Resistance at upper fixed point (Rᵤ) = 75 Ω

Temperature at lower fixed point (Tₗ) = 0 °C

Resistance at lower fixed point (Rₗ) = 63.00Ω

Resistance at room temperature (R) = 64.992 Ω

Room temperature (T) =?

T – Tₗ / Tᵤ – Tₗ = R – Rₗ / Rᵤ – Rₗ

T – 0 / 100 – 0 = 64.992 – 63  / 75 – 63

T / 100 = 1.992 / 12

Cross multiply

T × 12 = 100 × 1.992

T × 12 = 199.2

Divide both side by 12

T = 199.2 / 12

T = 16.6 °C

Thus, the room temperature is 16.6 °C

6 0
3 years ago
A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci
JulijaS [17]

Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

P = \frac{dW}{dt}

The work done by the spring is equal to the elastic potential energy stored in the spring.

U = \frac{1}{2}kx^2

The maximum energy stored in the spring is at the amplitude of the oscillation.

U_{max} =\frac{1}{2}kA^2

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)

When the mass reaches the amplitude:

A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi

because cos(π) = 1.

\omega t = \pi/2

Using ω = 2π/T,

\omega t = \pi/2\\\frac{2\pi}{T}t = \pi/2\\t = \frac{T}{4}

4 0
4 years ago
60 kilometers in 4 hours, what is the average speed?​
allsm [11]

Average speed = (distance covered) / (time to cover the distance)

Average speed = (60 kilometers) / (4 hours)

Average speed = (60/4) kilometer/hour

<em>Average speed = 15 km/hr</em>

8 0
3 years ago
A technician is checking refrigerant system pressures. Both high- and low-side service ports are located on the A/C compressor.
konstantin123 [22]

Answer:

Two major causes are outline bellow

1. The presence of air in the system

2. Clogged condenser

Explanation:

1. The presence of air in the system

One of the causes that have been established in relation to high compressor discharge pressure is the presence of air in the system. When this takes place, your best solution is to recharge the system.

2. Clogged condenser

Another is a clogged condenser in which case you will need to clean the condenser so that it will function properly. When you happen to spot that the discharge valve is closed and it is causing high discharge pressure on the compressor, you can solve that easily by opening the valve

5 0
4 years ago
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