Which decision-making strategy involves taking options off your list if they do not have a feature that is important to you?

The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

2, average velocity = -64.8 m/s

3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given by;

$y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}$

(1)

$y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s$

(2)

$y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s$

(3)

$y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s$

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

5 0

3 years ago

A commercial jet liner takes off with an average acceleration of 3 g. How long does it take to reach the end of its runway which

ANEK [815]

Answer:

The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

Explanation:

Given;

average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²

distance traveled by the commercial Jet liner, s = 1542 m

The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;

s = ut + ¹/₂at²

where;

u is the initial velocity of the commercial Jet liner = 0

s = 0 + ¹/₂at²

s = ¹/₂at²

2s = at²

$t = \sqrt{\frac{2s}{a} } \\\\t = \sqrt{\frac{2 \times 1524}{29.4} } \\\\t = 10.18 \ s$

Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

6 0

3 years ago

A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3

rosijanka [135]

The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
$A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2$

So the total charge on the surface of the sphere is, using the charge density
$\rho=+1.21 \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2$ :
$Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C$

The electrostatic force between the sphere and the point charge is:
$F=k_e \frac{Qq}{r^2}$
where
ke is the Coulomb's constant
Q is the charge on the sphere
$q=+1.75 \muC = +1.75 \cdot 10^{-6}C$ is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
$r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm$

8 0

3 years ago

Why do nuclear power plants use fission rather than fusion to generate

kicyunya [14]

B. Fusion requires very high pressure and temperature.

Explanation:

Nuclear fusion is the combination of atomic nuclei into larger ones with the release of a large amount of energy.

Nuclear fission is the decay process in which a heavy nuclide is bombarded with with neutrons.

Both processes release a huge amount of energy.
But fusion produces far more energy.
The reason why nuclear fusion is not in use is because of the high pressure and temperature needed start it.
The activation energy is high and the energy barrier is very great.
Only the core of the sun naturally favors fusion

learn more:

transmutation brainly.com/question/3433940

#learnwithBrainly

5 0

3 years ago

Read 2 more answers

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) A) 0.6976

soldier1979 [14.2K]

Answer:

The speed of the stone is 0.6138 c.

(B) is correct option.

Explanation: